Okay to find the perpendicular bisector of a segment you first need to find the slope of the reference segment.
m=(y2-y1)/(x2-x1) in this case:
m=(-5-1)/(2-4)
m=-6/-2
m=3
Now for the the bisector line to be perpendicular its slope must be the negative reciprocal of the reference segment, mathematically:
m1*m2=-1 in this case:
3m=-1
m=-1/3
So now we know that the slope is -1/3 we need to find the midpoint of the line segment that we are bisecting. The midpoint is simply the average of the coordinates of the endpoints, mathematically:
mp=((x1+x2)/2, (y1+y2)/2), in this case:
mp=((4+2)/2, (1-5)/2)
mp=(6/2, -4/2)
mp=(3,-2)
So our bisector must pass through the midpoint, or (3,-2) and have a slope of -1/3 so we can say:
y=mx+b, where m=slope and b=y-intercept, and given what we know:
-2=(-1/3)3+b
-2=-3/3+b
-2=-1+b
-1=b
So now we have the complete equation of the perpendicular bisector...
y=-x/3-1 or more neatly in my opinion :P
y=(-x-3)/3
<u>The x and y coordinates of the origin is equal to (0, 0), which is the point of intersection of the x-axis and y-axis. The x and y coordinates of a point on the x-axis is of the form (a, 0), and here the y coordinate of the point is equal to zero.</u>
The answer is 30
2 x 3 = 6
5 x 6 = 30
Comparing map distance to real distance we get 2cm/4km. That means 1cm = 2km.
So the map distance is half the real distance (well, technically not as one is in cm and the other in km but it’s enough to think this way) and a real distance of 10km must mean a map distance of half that (again ignoring the units) so we get 5cm.
