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2 years ago

What is the value of x?

Mathematics

1 answer:

alina1380 [7]2 years ago

4 0

answer is x=8

hope that helps lol

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What is the value of k in the product of powers below?

balu736 [363]

k=2

Step-by-step explanation:

since all the base are 10 you use the powers to solve it.

so it would be -3+1+k=-3=-3

3 0

3 years ago

Read 2 more answers

The graph of a linear function passes through the point (2,5) and a slope of 3

Delicious77 [7]

Answer:

$y=3x-1$

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=2\\y_1=5$ . We write

$(y-5)=3(x-2)$

Convert point slope form to slope intercept form by simplifying and rearranging.

$y-5=3(x-2)\\y-5=3x-6\\y=3x-1$

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3 years ago

A man tied a rope to the top of a tree, which is 'x' m tall. The other end of the rope was tied to

Monica [59]

Answer:

(x+16)^2=20^2+x^2

Step-by-step explanation:

Given there was no bending of the tree, the Pitagorean Theory would help finding the value of the trees hight.

x^2+32x+16^2=400+x^2

32x=(20-16)×(20+16)

x=144/32

x=4m and 50cm

4 0

3 years ago

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What is a possible absolute value inequality to represent -1

Bingel [31]

Answer:

Step-by-step explanation:

I believe the answer is one but I'm not 100% sure

7 0

3 years ago

A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes

marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

$V = s^2h = 5324$

$h = 5324 / s^2$

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top $s^2$

Side area 4sh

Total surface area $A = s^2 + 4sh$

We can substitute $h = 5324 / s^2$

$A = s^2 + 4s\frac{5324}{s^2}$

$A = s^2 + 21296/s$

To find the minimum of this function, we can take the first derivative, and set it to 0

$A' = 2s - 21296/s^2 = 0$

$2s = 21296/s^2$

$s^3 = 10648$

$s = \sqrt[3]{10648} = 22$

$h = 5324 / s^2 = 5324 / 22^2 = 11$

4 0

3 years ago