Hello :3
I believe your answer would be 1, 2 and 5.
Hope this helps!
Cupkake~
Answer:
Do you want a ligit answer or...
Explanation:
i will answer this, but youre gonna be scared if you ask me to do it.
B+ Bb Ww male × B+ Bb Ww female Because beardedness and coat color independently assort, we can treat them independently. The difference between this cross and a dihybrid cross is that the bearded allele B b is dominant in males and recessive in females. So we deal with male and female progeny separately. For each sex, then, we should get a typical dihybrid ratio. In males, the dominant phenotype is bearded, so we should get ¾ bearded, ¼ beardless. In females the dominant phenotype is beardless, so we should get ¾ beardless and ¼ bearded. Each sex will have ¾ black and ¼ white coats.
