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3 years ago

6. Circle all the expressions that are equivalent to this expression: 6p+ 7.

Mathematics

2 answers:

-BARSIC- [3]3 years ago

8 0

Number 4 and 6 are correct because you can only add variables with other variables so that is why 4 and 6 are correct

Leni [432]3 years ago

6 0

Answer:

Step-by-step explanation:

because the equation above says p+p+p+p+p+p+5+1+1

so if we add up the p's it will give us 6p and if we add up the nos it will give us 6p+7

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Could you guys simplify this for me please.. i’m not that good at math so I might as a few more

Nataly [62]

Answer:

Step-by-step explanation:

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3 years ago

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A game room has a floor that is 100 feet by 30 feet. A scale drawing of the floor on grid paper uses a scale of 3 units:5 feet.

Ghella [55]

3 units/ 5 feet = 60 units/ 100 feet
3 units/ 5 feet = 18 units/ 30 feet

The dimensions of the scale drawing are 60 units by 18 units.

Hope this helps!

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3 years ago

948÷ 10 to the 3rd power

Arturiano [62]

948/10 = 94.8^3 = 851,971.392

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3 years ago

63,825 in scientific notation

valentinak56 [21]

In scientific notation, in would be 6.3825*10 to the 4th power

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3 years ago

Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

$178=x^2+3x-y\\ \\ -6=4x-3y$

8 0

4 years ago

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