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Answer:
x^2(3x-2) cubic inches OR in^3
OR
3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3
I AM UNAWARE IF YOU ASKED THAT ONE SIDE IS (3X-2) OR ALL. I WILL ANSWER BOTH PARTS
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<em>NOTE</em><em>:</em><em> </em><em>'</em><em>^</em><em>'</em><em> </em><em>MEANS</em><em> </em><em>TO</em><em> </em><em>THE</em><em> </em><em>POWER</em><em> </em><em>OF</em><em>.</em><em>.</em>
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Volume = v, abc = 3 sides of cube (height, width, length)
Using the formula for volume in a cube,
We can solve this.
If one side is (3x-2)in,
- (3x-2)(x)(x) = v.... x are the other two sides
- x^2(3x-2) = v
x^2(3x-2) cubic inches OR in^3
If all sides are (3x-2)in,
Use the formula,
We can solve this.
- (3x-2)(3x-2)(3x-2) = v
- (3x-2)^3 = v.... 3x = a and -2 = b
- (3x)^3 + [(3)(3x)(2)][2-3x] - (2)^3 = v
- 27x^3 + 18x(2-3x) -8 = v
- (27x^3 + 36x - 54x^2) - 8 = v.. Terms inside brackets - take 3x as common and leave out 8
- 3x(9x^2 -18x +12) = v... Take 3 as common again in the brackets
- 3x [ 3 ([3x^2 -6x] + 4) -8 = v....Take 3x common in the terms in square brackets
- 3x [ 3 [ 3x (x-2) + 4 ]] - 8 = v
- 3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 = v
3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3
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Answer:
Step-by-step explanation:
Given
On first day bag contained 1 kernels
on second bag contained 2 kernels of corn
on third day bag contained 4 kernels of corn
on n th day bag contains kernels of corn
thus on 26 th day bag contains kernel
Each kernel weigh 0.07 gm
Therefore kernels weighs
Therefore on 26 th day kernel weighs 23,488.1024 kg