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Gnesinka [82]
2 years ago
8

Given the infinite series:

5%29%7D%2B%5Cfrac%7B1%7D%7B%285%29%287%29%7D%2B..." id="TexFormula1" title="\frac{1}{(1)(3)} +\frac{1}{(3)(5)}+\frac{1}{(5)(7)}+..." alt="\frac{1}{(1)(3)} +\frac{1}{(3)(5)}+\frac{1}{(5)(7)}+..." align="absmiddle" class="latex-formula">
a. Rewrite the series in sigma notation
b. Write an explicit formula for the nth partial sum
Mathematics
1 answer:
chubhunter [2.5K]2 years ago
8 0

a) The infinite series in <em>sigma</em> notation is described by this expression:

y = \sum \limits_{i=1}^{\infty} \frac{1}{i\cdot (i+2)}     (1)

b) The <em>explicit</em> formula for the n-th <em>partial</em> sum is represented by the following expression:

y = \frac{1}{i\cdot (i+2)}, i ∈ \mathbb{N}     (2)

<h3>How to derive an expression for a monotonous series</h3>

An infinite series is <em>monotonous</em> when it is <em>bounded</em>, that is, when the limit of the <em>infinite</em> series exists. In this case, we have an evidence of monotony in the denominators of the terms of the given series. In two consecutive terms, the latter always have a denominator greater than the former.

a) The series in <em>sigma</em> notation is now described below:

y = \sum \limits_{i=1}^{\infty} \frac{1}{i\cdot (i+2)}

b) The <em>explicit</em> formula for the n-th <em>partial</em> sum is defined by the expression within the sum, which is now presented below:

y = \frac{1}{i\cdot (i+2)}, i ∈ \mathbb{N}  

To learn more on infinite series: brainly.com/question/4268280

#SPJ1

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