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Gnesinka [82]
3 years ago
8

Given the infinite series:

5%29%7D%2B%5Cfrac%7B1%7D%7B%285%29%287%29%7D%2B..." id="TexFormula1" title="\frac{1}{(1)(3)} +\frac{1}{(3)(5)}+\frac{1}{(5)(7)}+..." alt="\frac{1}{(1)(3)} +\frac{1}{(3)(5)}+\frac{1}{(5)(7)}+..." align="absmiddle" class="latex-formula">
a. Rewrite the series in sigma notation
b. Write an explicit formula for the nth partial sum
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0

a) The infinite series in <em>sigma</em> notation is described by this expression:

y = \sum \limits_{i=1}^{\infty} \frac{1}{i\cdot (i+2)}     (1)

b) The <em>explicit</em> formula for the n-th <em>partial</em> sum is represented by the following expression:

y = \frac{1}{i\cdot (i+2)}, i ∈ \mathbb{N}     (2)

<h3>How to derive an expression for a monotonous series</h3>

An infinite series is <em>monotonous</em> when it is <em>bounded</em>, that is, when the limit of the <em>infinite</em> series exists. In this case, we have an evidence of monotony in the denominators of the terms of the given series. In two consecutive terms, the latter always have a denominator greater than the former.

a) The series in <em>sigma</em> notation is now described below:

y = \sum \limits_{i=1}^{\infty} \frac{1}{i\cdot (i+2)}

b) The <em>explicit</em> formula for the n-th <em>partial</em> sum is defined by the expression within the sum, which is now presented below:

y = \frac{1}{i\cdot (i+2)}, i ∈ \mathbb{N}  

To learn more on infinite series: brainly.com/question/4268280

#SPJ1

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if you are just given the two points it is the same formula. Find the midpoint between the points (4,−5) and (−4,5).
adell [148]

Answer:

M = (0,0)

Step-by-step explanation:

Given

(4,-5) and (-4,5)

Required

The midpoint (M)

This is calculated as:

M = \frac{1}{2}(x_1 + x_2,y_1+y_2)

So, we have:

M = \frac{1}{2}(4-4,-5+5)

M = \frac{1}{2}(0,0)

M = (0,0)

3 0
3 years ago
Cube root 343 ^-3/ root 4 81
zlopas [31]

Answer:

$\frac{1}{1029} $

Step-by-step explanation:

$\frac{\sqrt[3]{343^{-3}}}{\sqrt[4]{81} }  $

$\boxed{\text{Property: } a^{-b}=\frac{1}{a^{b}}} $

$\frac{\sqrt[3]{\frac{1}{343^{3}} }}{\sqrt[4]{81} }  $

$\frac{\frac{\sqrt[3]{1} }{\sqrt[3]{343^3} } }{\sqrt[4]{81} }  $

$\frac{\frac{1 }{343} }{3}  $

$\frac{342 \cdot \frac{1 }{343} }{343 \cdot 3}  $

$\frac{1}{1029} $

7 0
3 years ago
Brian has 64 flowers for a big party decoration. In addition, he is planning to buy some flower arrangements that have 18 flower
Volgvan

Answer:

The answer is 18x+64 ={the five terms it gives you} <(they might be different for everyone)

Step-by-step explanation:

I had the same question on my quiz and I used process of elimination to get the answer. According to my quiz, I'm assuming that you've had the same four answer choices that I had.

First off, the variable must be on 18, since it says 18 flowers each, which will eliminate two answer choices, another piece of evidence is that X is supposed to represent the numbers of flower arrangements.

Now we are left with two different answer choices, one of which is missing a term. This is a problem since it says that he has enough to have up to five of them. Since one of the answer choices has only four terms, it is safe to say it is incorrect.

Conclusion

This leads the answer to be 18x+64={five terms, not four}

I hope this helps, good luck on the rest of your assignment/quiz! :D

3 0
3 years ago
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