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2 years ago

(3rd grade question I’m helping my sister and I am stuck help)

Mathematics

1 answer:

goldenfox [79]2 years ago

3 0

Answer: See explanation.

Step-by-step explanation:

You need to put a little X on the graph down at the bottom on the ticks that represent 1/2, 3/4, 1 1/4, and 2.

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Find the value of x.

Allisa [31]

A straight line is 180°, so you can do:

109 + ? = 180 (? is the top angle of the triangle)

? = 71°

Because the triangle is an isosceles triangle, the other angle is 71° too.

71 + 71 + ? = 180

? = 38

You subtract 38 with 90 to find the other angle.

90 - 38 = 52°

To find ∠2 you subtract 52 with 180.

180 - 52 = 128

∠2 = 128

128 = 11x + 18

110 = 11x

10 = x

5 0

3 years ago

1) 17, 29, 32, 9, 30, 14, 8, 39, 11, 32, 23 Minimum : Maximum: Q1: Q2: Q3:

Lisa [10]

Answer:

Minimum: 8

Maximum: 39

Q1: 11

Q2: 23

Q3: 32

Step-by-step explanation:

Set the numbers into numerical order

8 9 11 14 17 23 29 30 32 32 39

Then separate into quarters

[8 9 11] [14 17 23] [29 30 32] 32 39

6 0

3 years ago

What is the LCD of , 3/4 ,4/5 and 7/10

lesantik [10]

Answer:

Step-by-step explanation:

20 is divisible by 4, 5 and 10

4 0

3 years ago

Charles smith makes $9.75 an hour he works four hours on Monday six hours on Tuesday five hours on Wednesday five hours on Thurs

ladessa [460]

Simple. Multiple

Monday: 6x9.75
Tuesday &Wednesday: 5x9.75
Thursday & Friday: 7x9.75

4 0

3 years ago

Read 2 more answers

Use the given degree of confidence and sample data to construct a confidence interval for the population mean mu.Assume that the

worty [1.4K]

Answer:

95% confidence interval for the true mean cholesterol content of all such eggs.

(173.8175 , 196.1825)

Step-by-step explanation:

Step(i):-

Given mean of the sample x⁻ = 185 milligrams

Given standard deviation of the sample 'S' = 17.6 milligrams

Level of significance

∝ = 0.05

$t_({\frac{\alpha }{2} , n-1 }) = t_{0.025 ,11} = 2.2010$

Step(ii):-

95% confidence interval for the true mean cholesterol content of all such eggs.

$(x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} })$

$(185 - 2.2010 \frac{17.6}{\sqrt{12} } , 185 + 2.2010 \frac{17.6}{\sqrt{12} })$

( 185 - 11.1825 , 185 + 11.1825)

(173.8175 , 196.1825)

Final answer:-

95% confidence interval for the true mean cholesterol content of all such eggs.

(173.8175 , 196.1825)

3 0

3 years ago