Question

Write the equation of a circle with endpoints of the diameter are (-8, 1) and (4,5)

Answer 1

centre of the circle =Midpoint of the diameter

centre of the circle=

$( \frac{ - 8 + 4}{2} , \frac{5 + 1}{2} ) = ( - 2 ,3)$

radius of the circle=

$\sqrt{(4 - ( - 2) ^{2} + (5 - 3 )^{2} } = \sqrt{36 + 4} = \sqrt{40 } = 2 \sqrt{10}$

equation of the circle: (x+2)²+(y-3)² = 40

ie.. x²+4x+4+ y²- 6y+ 9=40

ie... x²+y²+4x-6y-27=0

this is the answer......