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3 years ago

3) A 10kg object rests on a frictionless surface when it is struck by a 300N force. At what rate will it accelerate?

Physics

1 answer:

skad [1K]3 years ago

6 0

Answer: 0.3m/s/s

(i'm really sorry if i'm wrong)

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PLS HELPPPP AHHHH I WILL MARK AS BRAINLIEST

SIZIF [17.4K]

Answer:

Liquid

Explanation:

To turn liquid into gas, you add heat, to remove heat from gas, you make liquid.

8 0

2 years ago

How acceleration and gravitation (acceleration) are related/different?

mihalych1998 [28]

The source of acceleration (without gravity) is transfer of energy from one object to another or change of its own energy structure so that one of its components changes into increasing energy of motion.
But gravity occurs with no measurable energy transfer nor is the gravitating mass changing its energy structure in order to produce gravity.
If the cause of acceleration and gravity is not related at all is the Equivalence principle just a coincidence that the resulting effects are physically identical and indistinguishable

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4 years ago

Read 2 more answers

Need some help please

11Alexandr11 [23.1K]

Answer:

$x^2\neq -\frac{5}{13}$

First option

Explanation:

<u>Operations with functions </u>

Given two functions f, g, we can perform a number of operations with them including addition, subtraction, product, division, composition, and many others .

We have

$f(x)=20x^3-7x^2+3x-7$

$g(x)=-13x^2-5$

We are required to find

$\displaystyle \frac{f}{g}(x)$

We simply divide f by g as follows

$\displaystyle \frac{f}{g}(x)=\frac{20x^3-7x^2+3x-7}{-13x^2-5}$

We know rational functions may have problems if the denominator can be zero for some values of x. We must find out if there are such values and exclude them from the domain of the new-found function. We must ensure

$-13x^2-5\neq 0$

or equivalently

$x^2\neq -\frac{5}{13}$

Thus the first option is correct

Note: Since $x^2$ is always a positive number (for x real), our function does not really have any restriction in its domain

8 0

3 years ago

Calculate the acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds.

uysha [10]

Initial velocity=u=0.3m/s
Final velocity=v=0.7m/s
Time=t=30s

$\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf\longmapsto Acceleration=\dfrac{0.7-0.3}{30}$

$\\ \sf\longmapsto Acceleration=\dfrac{0.4}{30}$

$\\ \sf\longmapsto Acceleration=0.01m/s^2$

7 0

3 years ago

You are rolling on a skateboard with a constant velocity of 12 m/s. As you are moving you toss a baseball straight up into the a

Aliun [14]

Ick! Word problems! They suck. Okay so first of all you want to narrow it dow the equation.

Step 1. What are the numbers? (In this case 12 m/s and 25 m/s)

Step 2. Are you multiplying, dividing? (In this case your dividing)

Step 3. Divide.

I hope that helps.

5 0

3 years ago