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harkovskaia [24]
4 years ago
12

How acceleration and gravitation (acceleration) are related/different?

Physics
2 answers:
lukranit [14]4 years ago
7 0
Well, there's something called Gravitation acceleration which is the acceleration of an object due to a gravitational force. And maybe the difference is that gravity connects with the force of pulling downward, while acceleration can be increasing, possibly going up, forward, side to side, etc
mihalych1998 [28]4 years ago
5 0
The source of acceleration (without gravity) is transfer of energy from one object to another or change of its own energy structure so that one of its components changes into increasing energy of motion.
But gravity occurs with no measurable energy transfer nor is the gravitating mass changing its energy structure in order to produce gravity.
If the cause of acceleration and gravity is not related at all is the Equivalence principle just a coincidence that the resulting effects are physically identical and indistinguishable
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7. A stone is thrown horizontally with an initial
Kobotan [32]
The answer is (E) 8 s
5 0
3 years ago
a tungsten and coil has a resistance of 12 ohm at 15 degree celsius is the temperature coefficient of resistance of tungsten is
Dennis_Churaev [7]

Answer:

The resistance of the tungsten coil at 80 degrees Celsius is 15.12 ohm

Explanation:

The given parameters are;

The resistance of the tungsten coil at 15 degrees Celsius = 12 ohm

The temperature coefficient of resistance of tungsten = 0.004/°C

The resistance of the tungsten coil at 80 degrees Celsius is found using the following relation;

R₂ = R₁·[1 + α·(t₂ - t₁)]

Where;

R₁ = The resistance at the initial  temperature = 12 ohm

R₂ = The resistance of tungsten at the final temperature

t₁ = The initial temperature = 15 degrees Celsius

t₂ = The final temperature = 80 degrees Celsius

α = temperature coefficient of resistance of tungsten = 0.004/°C

Therefore, we have;

R₂ = 12×[1 + 0.004×(80 - 15)] = 15.12 ohm

The resistance of the tungsten coil at 80 degrees Celsius = 15.12 ohm.

6 0
3 years ago
Because of the high sugar and caffeine content in energy drinks, disregarding the unpredictable risks, what are two other increa
Wittaler [7]

Answer:

It increases heart rate and blood pressure, heart problems, dehydration, seizures, and dangerously high blood pressure. (From overconsumption of caffine.)

Explanation:

6 0
3 years ago
A pendulum takes 4 seconds to make one complete swing. A man walks 100m in a straight line while the pendulum makes 20 complete
irina [24]

The average velocity of the man is determined as 1.25 m/s.

<h3>Average velocity of the man</h3>

Total distance traveled by the man = 100 m

If 1 complete cycle = 4 s

  20 complete cycle = ?

= 20 x 4 s

= 80 s

Average velocity = total distance/total time

Average velocity = 100 m/80 s

Average velocity = 1.25 m/s

Thus, the average velocity of the man is determined as 1.25 m/s.

Learn more about average velocity here: brainly.com/question/6504879

#SPJ1

4 0
2 years ago
An electric turntable 0.730 mm in diameter is rotating about a fixed axis with an initial angular velocity of 0.240 rev/srev/s a
Zolol [24]

Answer:

a) \omega = 0.421\,\frac{rev}{s}, b) \Delta \theta = 0.066\,rev, c) v = 0.966\,\frac{mm}{s}, d) a = 3.293\,\frac{mm}{s^{2}}

Explanation:

a) The angular velocity of the turntable after 0.200\,s.

\omega = \omega_{o} + \alpha\cdot \Delta t

\omega = 0.240\,\frac{rev}{s}  + (0.906\,\frac{rev}{s^{2}} )\cdot (0.2\,s)

\omega = 0.421\,\frac{rev}{s}

b) The change in angular position is:

\Delta \theta = \omega_{o}\cdot t + \frac{1}{2} \cdot  \alpha \cdot t^{2}

\Delta \theta = (0.240\,\frac{rev}{s} )\cdot (0.2\,s) + \frac{1}{2}\cdot (0.906\,\frac{rev}{s^{2}} )\cdot (0.2\,s)^{2}

\Delta \theta = 0.066\,rev

c) The tangential speed of a point on the rim of the turn-table:

v = r\cdot \omega

v = (0.365\times 10^{-3}\,m)\cdot (0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )

v = 9.655\times 10^{-4}\,\frac{m}{s}

v = 0.966\,\frac{mm}{s}

d) The tangential and normal components of the acceleration of the turn-table:

a_{t} = (0.365\times 10^{-3}\,m)\cdot (0.906\,\frac{rev}{s^{2}})\cdot (\frac{2\pi\,rad}{1\,rev} )

a_{t} = 2.078\times 10^{-3}\,\frac{m}{s^{2}}

a_{t} = 2.078\,\frac{mm}{s}

a_{n} = (0.365\times 10^{-3}\,m)\cdot \left[(0.421\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )\right]^{2}

a_{n} = 2.554\times 10^{-3}\,\frac{m}{s^{2}}

a_{n} = 2.554\,\frac{mm}{s^{2}}

The magnitude of the resultant acceleration is:

a = \sqrt{(2.078\,\frac{mm}{s} )^{2}+(2.554\,\frac{mm}{s} )^{2}}

a = 3.293\,\frac{mm}{s^{2}}

8 0
3 years ago
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