Answer:
A) 2
Explanation:
Given;
magnetic field of the coil, B = 1.6 T
frequency of the coil, f = 75 Hz
maximum emf developed in the coil, E = 56.9 V
area of the coil, A = 0.15 m x 0.25 m = 0.0375 m²
The maximum emf in the coil is given by;
E = NBAω
Where;
N is the number of turns
ω is the angular velocity = 2πf = 2 x 3.142 x 75 = 471.3 rad/s
N = E / BAω
N = 56.9 / (1.6 x 0.0375 x 471.3)
N = 2 turns
Therefore, the value of N is 2
A) 2
The answer is horsts and grabens.
Lets use the expression
F = k*x
Where k is the spring constant [N/m]
And x the distance from the equilibrium position.
This force is equal to the force due to the acceleration of gravity
F = k*x = m*g
F = 525[N/m]* 0.30 [m] = 157.5 [N]
157.5 [N] = m *10[m/s**2] ...................> m = 15.75 kg
Answer:
C.Balanced... The force is balanced so neither one is being pulled harder...
Explanation:
Hope this helps!