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PtichkaEL [24]
2 years ago
11

Calculate the acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds.

Physics
1 answer:
uysha [10]2 years ago
7 0
  • Initial velocity=u=0.3m/s
  • Final velocity=v=0.7m/s
  • Time=t=30s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{0.7-0.3}{30}

\\ \sf\longmapsto Acceleration=\dfrac{0.4}{30}

\\ \sf\longmapsto Acceleration=0.01m/s^2

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Answer:

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Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

h=u't+\dfrac{1}{2}gt^2

h=\dfrac{1}{2}gt^2

h=\dfrac{1}{2}\times 9.8\times (4.3)^2

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Given that,

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The formula for the centripetal force is given by :

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