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PtichkaEL [24]
2 years ago
11

Calculate the acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds.

Physics
1 answer:
uysha [10]2 years ago
7 0
  • Initial velocity=u=0.3m/s
  • Final velocity=v=0.7m/s
  • Time=t=30s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{0.7-0.3}{30}

\\ \sf\longmapsto Acceleration=\dfrac{0.4}{30}

\\ \sf\longmapsto Acceleration=0.01m/s^2

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Answer:

number of Protons=16

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3 0
3 years ago
A ball of plasticine is released from rest at height of 2.2 m above the ground. After touching the ground, the plasticine ball c
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The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²

The direction of the acceleration of the ball is downwards

The given parameters

initial velocity of the ball, u = 0

height above the ground, h = 2.2 m

time of motion of the ball, t = 96 ms = 0.096 s

The magnitude of the acceleration of the ball while coming to rest is calculated as;

let the downwards direction of the acceleration be positive

h = ut + 0.5 at^2\\\\h = 0 + 0.5at^2\\\\h = 0.5 at^2\\\\a = \frac{h}{0.5t^2} \\\\a = \frac{2.2}{0.5 \times 0.096^2} \\\\a = 477.43 \ m/s^2

The direction of the acceleration of the ball is downwards

Learn more here: brainly.com/question/15407740

4 0
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Answer:

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