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2 years ago

Calculate the acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds.

Physics

1 answer:

uysha [10]2 years ago

7 0

Initial velocity=u=0.3m/s
Final velocity=v=0.7m/s
Time=t=30s

$\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf\longmapsto Acceleration=\dfrac{0.7-0.3}{30}$

$\\ \sf\longmapsto Acceleration=\dfrac{0.4}{30}$

$\\ \sf\longmapsto Acceleration=0.01m/s^2$

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Answer:

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Explanation:

It is given that,

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Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

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Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

$h=u't+\dfrac{1}{2}gt^2$

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$h=\dfrac{1}{2}\times 9.8\times (4.3)^2$

h = 90.60 meters

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Given that,

Mass of a tribble, m = 2.5 kg

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