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gtnhenbr [62]
3 years ago
7

Given this parallelogram, find x? Pls help ;(

Mathematics
1 answer:
Juliette [100K]3 years ago
7 0
Y’know what, it’s been a long time doing that, but I tried it out for you. This is what I got. Somebody please correct me if I’m wrong.

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What is the answer to this?
nekit [7.7K]

Answer:

Up

Step-by-step explanation:

Y= 1x^2 + 3x + 9

Y= Ax^2 + Bx + C

To determine which way a parabola opens just look at the coefficient (the number) of the x^2 - Always use the coefficient that is beside the x^2

So,  if the coefficient A is positive the parabola is opening upward

      if the coefficient A is negative the parabola is opening downward

7 0
2 years ago
Read 2 more answers
So here's the question
Lesechka [4]
Yes, is subtraction, to get their "difference".

first off, let's convert the mixed fractions, to "improper", and then subtract.

\bf \stackrel{red~yarn}{9\frac{1}{5}}-\stackrel{blue~yarn}{3\frac{11}{25}}

\bf -------------------------------\\\\
\stackrel{mixed}{9\frac{1}{5}}\implies \cfrac{9\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{46}{5}}
\\\\\\
\stackrel{mixed}{3\frac{11}{25}}\implies \cfrac{3\cdot 25+11}{25}\implies \stackrel{improper}{\cfrac{86}{25}}\\\\
-------------------------------\\\\
\cfrac{46}{5}-\cfrac{86}{25}\impliedby \textit{our LCD is 25}\implies \cfrac{(5\cdot 46)~~-~~(1\cdot 86)}{25}
\\\\\\
\cfrac{230~-~86}{25}\implies \cfrac{144}{25}\implies 5\frac{19}{25}
4 0
3 years ago
Find the coordinates of the intersection of the diagonals of parallelogram QRST with vertices Q(−8, 1), R(2, 1), S(4,−3), and T(
FinnZ [79.3K]

Answer:

(-2,1)

Step-by-step explanation:

6 0
3 years ago
The velocity of a body is increases from 10 m/s ti 15 m/s in 5seconds calculate its acceleration​
larisa [96]

Answer:

accelaration =  \frac{change \: in \: veloity}{time}  \\  =  \frac{15 - 10}{5}  \\  =  \frac{5}{5}  \\  = 1 \frac{m}{ {s}^{ - 2} }

3 0
3 years ago
Read 2 more answers
‼️‼️‼️‼️ pls, i need help
zepelin [54]
Yo soy muy grande cojones y muy grande Pena!!!!!!
7 0
3 years ago
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