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Margaret [11]
3 years ago
9

Find the probability of this event Enter the answer as a fraction in simplest form, as a decimal, and as a

Mathematics
2 answers:
Nat2105 [25]3 years ago
6 0

Answer:

1/5.

Step-by-step explanation:

First you have to add up all of the numbers: 12+12+4+6+26. Then you have to find how many red marbles there are, which this case there are 12, so you get your fraction of 12/60 which can be reduced to 1/5.

Step2247 [10]3 years ago
3 0

Answer:

12+12+4+6+26=50

12/50=6/25=0.24=24%

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Gm everyone plz help with this question down below :) Who was Sherlock Holmes?
kenny6666 [7]

Answer:

Sherlock Holmes is a fictional detective created by British author Sir Arthur Conan Doyle. 

7 0
2 years ago
Read 2 more answers
Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type.
Vinvika [58]

Answer:

The point estimate for population mean is 8.129 Mpa.

Step-by-step explanation:

We are given the following in the question:

Data on flexural strength(MPa) for concrete beams of a certain type:

11.8, 7.7, 6.5, 6.8, 9.7, 6.8, 7.3, 7.9, 9.7, 8.7, 8.1, 8.5, 6.3, 7.0, 7.3, 7.4, 5.3, 9.0, 8.1, 11.3, 6.3, 7.2, 7.7, 7.8, 11.6, 10.7, 7.0

a) Point estimate of the mean value of strength for the conceptual population of all beams manufactured

We use the sample mean, \bar{x} as the point estimate for population mean.

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

\bar{x} = \dfrac{\sum x_i}{n} = \dfrac{219.5}{27} = 8.129

Thus, the point estimate for population mean is 8.129 Mpa.

4 0
3 years ago
What is the measure of ZRMN?
Volgvan
Yes! Yup your right! Congrats yup!
3 0
2 years ago
- Let y represent the width of a rectangle and let x represent the rectangle's lengu.
valentina_108 [34]

Answer:

Length: 21 cm and Width:  6cm

Step-by-step explanation:

Let y be the width and x length of the rectangle. We know:

x = 4y -3 -------- eq. 1

54 = 2x + 2y    (Perimeter of the rectangle) ------- eq.  2

Substitute equation 1 in equation 2:

54 = 2(4y-3) + 2y\\54 = 8y - 6 + 2y\\54 + 6 = 8y + 2y\\60 = 10 y\\\\\frac{60}{10}= y\\y = 6

Using the value of y, we find x.

x = 4y - 3\\x = 4(6) -3\\x= 24 - 3\\x = 21

4 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
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