Answer:
1/2
Step-by-step explanation:
Answer:
I dont understand that sorry
Answer:
its the 3 one
Step-by-step explanation:
To factor out you have to think what multiples to AC and adds to B.
Ax^2+Bx+C
So... for this problem AxC=1x-24 or -24
B is -2.
So what two numbers multiply to -24: -3x8, -8x3, -4x6, -6x4, -2x12, -12x2.
Out of these, which adds to -2: -6+4=-2.
So the factors are (d-6)(d+4)
OR the longer way, which you really only use if A is not equal to 1.
Use the terms above and then rewrite the equation with two middle terms: d^2+4d-6d-24
Group the terms by using addition: (d^2+4d)+(6d-24)
Find what they have in common and factor it out. For the first, it's d. They both have d. So: d(d+4)
To check this, distribute the d. It should equal the first set lf parenthesis.
For the second, they have a number in common. 6 is a multiple of 24 so you can take that out: -6(d+4)
If the terms inside the parenthesis are the same, that's good. It means we can pair the insides and the outsides together to form the factors.
The two terms outside the parenthesis: d, -6 group together and become (d-6)
The inside terms stay the same: (d+4)
(d-6)(d+4)
Again, this is the longer way and no necessary for a problem like this. But if it was 2d^2, then this would be perfecf.
Answer:
<em>The area of the shaded part = 61.46</em>
<em />
Step-by-step explanation:
Assume the hypotenuse of the triangle is c (c>0)
As the triangle inscribed in the semi circle is the right angle triangle, its hypotenuse is equal to the diameter of the circle.
The hypotenuse of the triangle can be calculated by Pythagoras theorem as following: ![c^{2} =a^{2} +b^{2} =(2\sqrt{5}) ^{2} + (4\sqrt{5}) ^{2} = 20 + 80 = 100](https://tex.z-dn.net/?f=c%5E%7B2%7D%20%3Da%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3D%282%5Csqrt%7B5%7D%29%20%5E%7B2%7D%20%2B%20%284%5Csqrt%7B5%7D%29%20%5E%7B2%7D%20%3D%2020%20%2B%2080%20%3D%20100)
=> c = 10
So that the semi circle has the diameter = 10 => its radius = 5
- The total area of 2 semi circles is equal to the area of the circle with radius =5
=> The total area of 2 semi circles is:
x
= 25![\pi](https://tex.z-dn.net/?f=%5Cpi)
- The area of a triangle inscribed in the semi circle is: 1/2 x a x b = 1/2 x
x
= 20
=> The area of 2 triangles inscribed in 2 semi circles is: 2 x 20 = 40
- The area of the square is:
= ![10^{2} =100](https://tex.z-dn.net/?f=10%5E%7B2%7D%20%3D100)
It can be seen that:
<em>The area of the shaded part = The area of the square - The total area of 2 semi circles + The total are of 2 triangles inscribed in semi circles </em>
<em>= 100 - 25</em>
<em> + 40 = 61.46</em>