Step-by-step explanation:
it is an isoceles triangle (equally long legs).
there is a right angle at W, so YW is the height of the isoceles triangle XYZ.
that means W splits XZ in half.
therefore,
ZW = XZ/2 = 38/2 = 19
To compare the numbers, go from left to right examining the numbers carefully. so look at a., 3.7 can be written as 3.700, if u look, 3 and 0, it is definetly bigger than 0.01 and 0.001
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Answer:
y=7x-188
Step-by-step explanation:
We know that this line must have a slope of 7, because this line is parallel to y=7x+13
We must use the point slope formula: y-
= m(x-
)
Next, we will plug in the point (28,8) for
and
, and 7 in for m
y-8=7(x-28)
Solve the equation, first by distributing the 7
y-8=7x-196
Add the 8 over
y=7x-188
Answer:
Tyler's height in centimeters is, 144.78 centimeters.
Step-by-step explanation:
Given the statement: Tyler's height is 57 inches.
To find his height in centimeters.
Using the conversion:

Proportion states that the two ratios or fraction are equal.
Using proportion method:
By cross multiply, we get
centimeters.
therefore, his height in centimeter is, 144.78 inches.