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mamaluj [8]
2 years ago
9

1. ENTRADAS Cuatro amigos compraron entradas de cine por $ 41. Al día siguiente, siete

Mathematics
1 answer:
Roman55 [17]2 years ago
5 0

Answer:

el precio de un boleto es $10.25

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Tom throws a Frisbee into the air from a height of 4 feet with
siniylev [52]

Answer:

68 feet

Step-by-step explanation:

Vertical motion model:

h = -16t² + vt + s

Given v = 64 and s = 4:

h = -16t² + 64t + 4

This is a parabola.  The maximum of a parabola is at the vertex.

For y = ax² + bx + c, the vertex is at x = -b/(2a).

Therefore, the time to reach the maximum height is:

t = -64 / (2 × -16)

t = 2

And the maximum height is:

h = -16(2)² + 64(2) + 4

h = 68

So the Frisbee reaches a maximum height of 68 feet.

5 0
3 years ago
No links pls no links
vodka [1.7K]

Answer:

ok byyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyee6648479786100101010101001010101010010010101001010100101010101010010101001010101110100010100101101001010101001010101000010101010011001010101010010101001

Step-by-step explanation:1001010101001010101001010101010010101010101001010101010101010100101010101010101010101010101010000000000000000111111111110000000001010101001010101010

7 0
3 years ago
Point T has coordinates (10,20). To calculate the coordinates of point T′ in the image,
Hatshy [7]

Answer: T'(18,36)

Step-by-step explanation:

For this exercise it is important to know the definition of "Dilation".

 A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.

If the Dilation is centered at the origin, and knowing the scale factor of \frac{9}{5}, you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.

Knowing that the point T has the following coordinates:

T(10,20)

You get that the coordinates of the Image T' are the shown below:

T'=(\frac{9}{5}*10,\frac{9}{5}*20)\\\\T'=(18,36)

6 0
3 years ago
The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....
leonid [27]

Answer:

Step-by-step explanation:

Let the solution to

2x^2 + x -1 =0

x^2+ (1/2)x -(1/2)

are a and b

Hence a + b = -(1/2) ( minus the coefficient of x )

ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

2x^2-19x + 44 =0

B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

x^2 +(3/2) x -9/2 = 0

2x^2 + 3x -9 =0.

4 0
3 years ago
261,177 is farther or closer to 300000
lutik1710 [3]
Actually is close, like rounding anything above 5 is rounded up, 5 and below stays the same. It's 261,177 that means it is around 40,000 away from 300,000. Therefore is it closer
7 0
3 years ago
Read 2 more answers
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