Divide 48 by 4 to see how many are in one.
it's 1 box containing 12
Answer:
5x-12 / (x+3)(x-3)
Step-by-step explanation:
Given expression:\frac{3}{x^2-9}+\frac{5}{x+3}
Using identity a^2-b^2=(a+b)(a-b), we get
=\frac{3}{(x+3)(x-3)}+\frac{5}{x+3}
Taking L.C.M. of the denominator, we get
\frac{3+5(x-3)}{(x+3)(x-3)}=\frac{3+5x-15}{(x+3)(x-3)}
=\frac{5x-12}{(x+3)(x-3)}
\Rightarrow\frac{3}{x^2-9}+\frac{5}{x+3}=\frac{5x-12}{(x+3)(x-3)}
Given:
Triangle DEF
To find:
The perimeter of triangle DEF.
Solution:
Coordinate of D = (-1, 1)
Coordinate of E = (2, 1)
Coordinate of F = (-1, 4)
Distance formula:
<u>Distance of DE:</u>
Here, 
d = 3 units
<u>Distance of EF:</u>
Here, 
d = 4.2 units
<u>Distance of FD:</u>
Here, 
d = 3 units
Perimeter of ΔDEF = DE + FE + FD
= 3 + 4.2 + 3
= 10.2 units
The perimeter of triangle DEF is 10.2 units.
If you make 60 become 6 and 20 become 2, then multiply them both by eachother you get 30. Add a zero to compensate for the ones you took out of the other 2 number. There ya go
I forgot but I used to know this one
