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Paraphin [41]
3 years ago
5

Think of a body which is at rest but not in equilibrium

Physics
1 answer:
REY [17]3 years ago
8 0

Answer:

I think the sun is the right answer

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A 48.9 kg meteor is moving in outer space. If a 8.6 N force is applied opposite the direction of motion, what is the deceleratio
nalin [4]

Answer:

The deceleration is 0.18 m/s²

Explanation:

Hi there!

Using Newton´s second law, we can calculate the deceleration:

∑F = m · a

Where:

∑F = the sum of all forces in a given direction.

m = mass of the object.

a = acceleration.

Solving for a:

∑F/m = a

The only force acting on the meteor is the applied force of 8.6 N. So, the acceleration will be:

8.6 N / 48.9 kg = a

a = 0.18 m/s²

The deceleration is 0.18 m/s² or, in other words, the acceleration is -0.18 m/s²

Have a nice day!

3 0
3 years ago
A vector has an x-component of -7.55m and a y-component of -2.48. Find the direction of the vector
Sedbober [7]

Answer:

198.2°

Explanation:

The angle from the +x axis can be found with:

θ = atan(vy / vx)

Given vx = -7.55 and vy = -2.48:

θ = atan(-2.48 / -7.55)

θ = 18.2°, 198.2°

Since θ is in the third quadrant, θ = 198.2°.

8 0
4 years ago
What types of bond forms when two or more atoms share electrons?
atroni [7]
D) Hydrogen is the correct/ right answer because it says in the science book in the chapter that it is on to find the correct answer as well as look in the chapter that is on and look on the pages
8 0
3 years ago
Read 2 more answers
Name the planets to which these moons belong
yuradex [85]
The moons belong to the following planets in the following order:

1. Callisto ==> Jupiter
2. Deimos ==> Mars
3. Europa ==> Jupiter
4. Ganymede ==>Jupiter
5. Triton ==> Neptune
6. Titan ==> Saturn
7. Phobos ==> Mars
8. Io ==> Jupiter

Hope that helped =)
4 0
3 years ago
The continuity equation shows that the ratio of fluid velocities within different openings is inversely proportional to the cros
Stolb23 [73]

Answer:

A typical example of where the continuity equation can be applied, is in finding the cross sectional area of a laminar falling stream of water from a pipe at an elevation, at the point where it hits the ground.

The speed of the water through the discharge opening of the pipe can be measured with a flow-meter, and the cross sectional opening of the pipe is known.

As the water leaves the pipe, and falls towards the ground, the water stream is accelerated under gravity, and the speed of the water stream increase. The increase in the speed of the water stream causes the cross sectional area to decrease in obedience of the continuity law and equation. If the speed of can be measured, then the area of the water stream just before the water touches the ground  can be calculated from the continuity equation.

If the speed of the water stream can not be measured, then it can be calculated using Newton' equation of motion

v^{2} = u^{2} + 2gz

v = \sqrt{u^{2} + 2gz}

where

v = the velocity of the water stream at the point where it hits the ground

u = the velocity of the water at the pipe discharge (measured with a flow meter in the pipe)

g = acceleration due to gravity

z = the elevation of the pipe above the ground.

After calculating the speed of the water stream at the point where it hits the ground, the cross sectional area of the the stream can be calculated from the continuity equation.

uA = va

where

u and v are the velocities of the water stream at the pipe discharge and at the ground respectively.

A = the cross sectional area of the pipe

a = the area of the water stream before it hits the ground.

the equation is simplified as

a = \frac{uA}{v}

7 0
4 years ago
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