Question

The equation y2/100+x2/4 =1 represents an ellipse. Which points are the vertices of the ellipse? (−10, 0) and (10, 0) (−2, 0) and (2, 0) (0, −10) and (0, 10) (0, −2) and (0, 2)

Answer 1

Answer:

see explanation

Step-by-step explanation:

For the ellipse

$\frac{x^2}{a^2}$ + $\frac{y^2}{b^2}$ = 1

Then the vertices are (a, 0), (- a, 0) and (0, b), (0, - b)

Given

$\frac{y^2}{100}$ + $\frac{x^2}{4}$ = 1

Then

a² = 4 ⇒ a = 2 and b² = 100 ⇒ b = 10

Hence the vertices are

(2, 0), (- 2, 0) and (0, 10), (0, - 10)

Answer 2

Answer:

The vertices of the ellipse are the points (0 , -10) and (0 , 10) ⇒ 3rd answer

Step-by-step expenation

its answer C. i just took the test