The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
<h3>What is the interest rate behind a pay back?</h3>
In this situation we assume that the loan does not accumulate interests continuously in time. Hence, the <em>interest</em> rate for paying the loan back 75 days later is:
575 = 525 · (1 + r/100)
50 = 525 · r /100
5000 = 525 · r
r = 9.524
The loan has an <em>interest</em> rate of 9.524 % for 75 days. <em>Simple annual interest</em> rate is determine by rule of three:
r' = 9.524 × 365/75
r' = 46.350
The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
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The correct answer for each is
a= 390.8
b= 136.8
<u>Option C is correct </u><u>(y + z = 6) ⋅ −3</u>
What is a linear equation in math?
- A linear equation only has one or two variables.
- No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction.
- When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.
As per the statement -
A student is trying to solve the system of two equations given below:
Equation P: y + z = 6 ....[1]
Equation Q: 3y + 4z = 1 ....[2]
Multiply the equation [1] by -3 to both sides we have;
-3 .( y + z = 6 ) ⇒ -3y -3z = -18..........(3)
Add equation [2] and [3] to eliminate the y-term;
z = -17
Therefore, the possible step used in eliminating the y-term is, (y + z = 6) ⋅ −3
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<u>The complete question is -</u>
A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 3y + 4z = 1 Which of these is a possible step used in eliminating the y-term?
(y + z = 6) ⋅ 4
(3y + 4z = 1) ⋅ 4
(y + z = 6) ⋅ −3
(3y + 4z = 1) ⋅ 3
Answer:
Step-by-step explanation:
The remainder is 10!
Hope it helps
Answer:
The answer is -1/2
Step-by-step explanation:
We first start by removing x in order isolate the y variable
2y = 6 - x
y = 
Further, we simplify the equation in order to get the value of m (slope)
y = 3 + 
Therefore, our slope is equivalent to -1/2
