Determine the empirical formula for the compound that has 71.98% C, 6.71% H and 21.31% O.

2 answers:

6 0

Answer:

Benzyl Acetate C9H10O2

Explanation:

labwork [276]3 years ago

5 0

Answer:

Explanation:

No problem m8374893724873284972384823749832748937249873298478274923874983249872398479832497234

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