Question

Assuming the metals lose all their valence electrons and the nonmetals gain electrons to complete the s-p subshells, which listing below shows the correct information for the element?Elements Electron Structure of Atom Electron Structure of Ion Net Ion Charge:1. sodium 1s22s22p63s1 1s22s22p6 -12. fluorine 1s22s22p4 1s22s22p6 -13. aluminum 1s22s22p63s23p1 1s22s22p6 +3a. The listing for sodium is correct.b. The listing for fluorine is correct.c. The listing for aluminum is correct.d. None of these

Answer 1

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{1}$. When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.

$Na^{+}$ : $1s^{2}2s^{2}2p^{6}$

Atomic number of fluorine is 9 and its electronic configuration is $1s^{2}2s^{2}2p^{5}$. When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.

$F^{-}$ : $1s^{2}2s^{2}2p^{6}$

Atomic number of aluminium is 13 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$. When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.

$Al^{3+}$ : $1s^{2}2s^{2}2p^{6}$

Thus, we can conclude that the listing for aluminum is correct.