<u>ANSWER</u>
1. ![x=\frac{1}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B2%7D)
2. ![x=1](https://tex.z-dn.net/?f=x%3D1)
<u>QUESTION 1</u>
The first sentence is
.
Recall that;
![(a^m)^n=a^{mn}](https://tex.z-dn.net/?f=%28a%5Em%29%5En%3Da%5E%7Bmn%7D)
We simplify the left hand side by applying this property to get;
.
.
We now rewrite the right hand side too in an index form to obtain;
![\Rightarrow 5^{1}=5^{2x}](https://tex.z-dn.net/?f=%5CRightarrow%205%5E%7B1%7D%3D5%5E%7B2x%7D)
We now equate the exponents to get;
.
![\Rightarrow \frac{1}{2}=x](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%7B1%7D%7B2%7D%3Dx)
.
<u>QUESTION 2</u>
The second sentence is ![(8^{\frac{1}{3}})^2=4^x](https://tex.z-dn.net/?f=%288%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E2%3D4%5Ex)
We simplify the left hand side first to get;
![(2^{3\times \frac{1}{3}})^2=4^x](https://tex.z-dn.net/?f=%282%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%7D%29%5E2%3D4%5Ex)
![2^2=4^x](https://tex.z-dn.net/?f=2%5E2%3D4%5Ex)
We now rewrite the left hand side too in index form to obtain;
![2^2=2^{2x}](https://tex.z-dn.net/?f=2%5E2%3D2%5E%7B2x%7D)
We equate the exponents to get;
![2=2x](https://tex.z-dn.net/?f=2%3D2x)
This implies that;
![1=x](https://tex.z-dn.net/?f=1%3Dx)
or
![x=1](https://tex.z-dn.net/?f=x%3D1)
Answer:
D 1/4
Step-by-step explanation:
A. I think the cordinate of the meeting place will be 11,11 and for B I don't even know why that's there..
C. I think it's 11 too. Idk but, when you check ur homework you can ask ur teacher/parent for help.
Answer:
See Explanation;
Step-by-step explanation:
The given vectors are;
and ![v_2=\:\:](https://tex.z-dn.net/?f=v_2%3D%5C%3A%3C%5C%3A5%2C-3%3E%5C%3A)
a) To add or subtract two vectors, we add or subtract their corresponding components
![v_1+v_2=\:\:+\:\:](https://tex.z-dn.net/?f=v_1%2Bv_2%3D%5C%3A%3C%5C%3A1%2C6%3E%5C%3A%2B%5C%3A%3C%5C%3A5%2C-3%3E%5C%3A)
![v_1+v_2=\:\:](https://tex.z-dn.net/?f=v_1%2Bv_2%3D%5C%3A%3C%5C%3A1%2B5%2C6%2B-3%3E%5C%3A)
![v_1+v_2=\:\:](https://tex.z-dn.net/?f=v_1%2Bv_2%3D%5C%3A%3C%5C%3A6%2C3%3E%5C%3A)
![v_1-v_2=\:\:-\:\:](https://tex.z-dn.net/?f=v_1-v_2%3D%5C%3A%3C%5C%3A1%2C6%3E%5C%3A-%5C%3A%3C%5C%3A5%2C-3%3E%5C%3A)
![v_1-v_2=\:\:](https://tex.z-dn.net/?f=v_1-v_2%3D%5C%3A%3C%5C%3A1-5%2C6--3%3E%5C%3A)
![v_1-v_2=\:\:](https://tex.z-dn.net/?f=v_1-v_2%3D%5C%3A%3C%5C%3A-4%2C9%3E%5C%3A)
![v_2-v_1=\:\:-\:\:](https://tex.z-dn.net/?f=v_2-v_1%3D%5C%3A%3C%5C%3A5%2C-3%3E%5C%3A-%5C%3A%3C%5C%3A1%2C6%3E%5C%3A)
![v_2-v_1=\:\:](https://tex.z-dn.net/?f=v_2-v_1%3D%5C%3A%3C%5C%3A5-1%2C-3-6%3E%5C%3A)
![v_2-v_1=\:\:](https://tex.z-dn.net/?f=v_2-v_1%3D%5C%3A%3C%5C%3A4%2C-9%3E%5C%3A)
b) See attachment for graphs(1,6
Answer:
you divide 15 by 2 to get the radius, then do pie times radius to the second power, so
3.14*7.5*7.5= 23.55
that is ur answer!
Step-by-step explanation: