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3 years ago

Help I will be marking brainliest!!!

Mathematics

1 answer:

Margarita [4]3 years ago

7 0

You use the tan/cos/sin rules

So we know that the hypotenuse=46.8, opposite=44

We can use sin (negative) to find it

sin^-1=opp/hyp
sin^-1=44/66.8
=70 degrees

Hope this helps!! :)

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Please help ASAP!!

marta [7]

Answer:

D. NM=12; mK=70°

Step-by-step explanation:

KN≈KM so they have the same 55° and then

180°-55°-55°=70° and

6*2=12

3 0

3 years ago

Let f(t) give the number of liters of fuel oil burned in t days, and w(r) the liters burned in r weeks. Find a formula for w by

viktelen [127]

Answer:

7 f(t)

Step-by-step explanation:

So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.

w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.

As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:

w(r) = w[7f(t)]

So, we represented the liters in one week by it measure of days.

So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:

w (r) = w[7 f(t)] = 7 f(t)

Here we hace the w function represented in terms of t instead of r.

3 0

3 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Anika [276]

Answer:

Step-by-step explanation:

5(2) - (2)^3 = 10 - 8 = 2

3 0

3 years ago

Selmas class making a care package to give to victims of a natural disaster.Selma packs one box in 5 minutes and has already pac

bixtya [17]

Each of them need to work 105 minutes more in order to have packed the same number of boxes.

Explanation

Suppose, they need to work for $x$ minutes more in order to have packed the same number of boxes.

Selma packs one box in 5 minutes and Trudy packs one box in 7 minutes.

So, the number of boxes packed by Selma in that $x$ minutes $=\frac{x}{5}$ and the number of boxes packed by Trudy in $x$ minutes $=\frac{x}{7}$

Given that, Selma and Trudy have already packed 12 and 18 boxes.

Now if each of them packed the same number of boxes, then the equation will be......

$12+\frac{x}{5}=18+\frac{x}{7}\\ \\ \frac{x}{5}-\frac{x}{7}= 18-12\\ \\ \frac{7x-5x}{35}=6\\ \\ \frac{2x}{35}=6\\ \\ 2x= 210\\ \\ x= \frac{210}{2}=105$

So, each of them need to work 105 minutes more in order to have packed the same number of boxes.

6 0

3 years ago

1. Which of the following is the square of a binomial? O a2 + b2 O 16x2 +9y2 O m2-mn + n2 O c2-2cd+d2

melomori [17]

Answer:

i guess it's the second one, 16x2+9y2, since they are both raised to 2 and they are binomial

6 0

3 years ago