Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
1 3/7 or 10/7 I took the test aswell
Answer:
<PCH+<HCK=180-DEGREE BEING IN A STRAIGHT LINE.
3M+58+8M+155=180
11M=180-213
11M=-33
M=-3
SO,
<PCH
3M+58
=3*(-3)+58
=58-9
=49-DEGREE
123.5%
= 123.5/100
= 1235/1000
= (1235/5) / (1000/5)
= 247/200
= 1 47/200
The final answer is 247/200 or 1 47/200~
