All categories

2 years ago

Find the answer to: (k+3)-(3k-5)=

Mathematics

1 answer:

Degger [83]2 years ago

4 0

Answer:

-2k + 8

Step-by-step explanation:

Distribute the Negative Sign:

=k + 3 + −1(3k − 5)

=k + 3 + −1(3k) + (−1)(−5)

=k + 3 + −3k + 5

Combine Like Terms:

=k + 3 + −3k + 5

=(k + −3k) + (3 + 5)

=−2k + 8

Hope this helps!

brainliest?

You might be interested in

Suppose you have 100 ft of string to rope off a rectangular section for a bake sale at a school Fair. The function A=x^2+50x giv

cupoosta [38]

Answer:

Therefore the width is 25 feet for getting maximum area.

The maximum area of the rectangle is 625 square feet.

Therefore the range is 0≤A≤625.

Step-by-step explanation:

Given function is

A = - x²+50x

We know that ,

If y = ax²+bx+c

For the maximum $x=-\frac{b}{2a}$

Here a = -1 , b= 50 and c=0

Therefore the width $x= -\frac{50}{2.(-1)} = 25$

Therefore the width is 25 feet for getting maximum area.

The maximum area =[ -(25)²+50.25] square feet

= 625 square feet

The area can not be negative and maximum area is 625 square feet.

Therefore the range is 0≤A≤625.

5 0

3 years ago

Toms house cost $100000 in the year 2000 in 2008 he sold his house for 125000 what was the percentage of change in the price of

Leno4ka [110]

There was a 125% change in the price of the house.

The changed price was an increase of from the original 100,000 therefore the answer can be concluded to be above 100%.

Anyways, to solve this problem you need to find what 125,000 is OF 100,000, meaning you need to divide. 125,000/100,000=1.25. 1.25 can then be changed into 125%.

8 0

3 years ago

Read 2 more answers

You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was

Doss [256]

Answer:

A) The linear relation between price and demand is:

$d=-550x+2750$

The revenue R is:

$R=-550x^2+2750x$

B) The profit functionP is:

$P=-550x^2+2750x-30$

C) The largest monthly profit is obtained with a log-on fee of $2.5 per month. This corresponds to a profit of $3407.5.

Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

At price x=3, the demand is d=1100.
At price x=2.5, the demand is d=1375.

We will model the relation:

$d=mx+b$

We can calculate the slope m as:

$m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550$

Then, replacing one point in the linear equation, we can calculate the intercept b:

$d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750$

Then, the linear relation between demand and price is:

$d=-550x+2750$

The revenue R can be expressed as the multiplication of the price and the demand:

$R=x\cdot d=x(-550x+2750)=-550x^2+2750x$

If we have a fixed cost of $30 per month, the profit P is:

$P=R-FC=-550x^2+2750x-30$

We can maximize the profit by deriving the profit function and making it equal to zero.

$\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5$

This corresponds to a profit of:

$P(2.5)=-550(2.5)^2+2750(2.5)-30\\\\P(2.5)=-550\cdot 6.25+6875-30\\\\P(2.5)=-3437.5+6875-30\\\\P(2.5)=3407.5$

5 0

3 years ago

How can you classify this triangle? A. scalene, acute B. scalene, obtuse C. isosceles, right I D. isosceles, obtuse

timofeeve [1]

Answer:

D. obtuse isosceles

Step-by-step explanation:

An obtuse triangle has one angle measuring more than 90º but less than 180º (an obtuse angle). It is not possible to draw a triangle with more than one obtuse angle. Note: It is possible for an obtuse triangle to also be scalene or isosceles. An equiangular triangle has three congruent angles.

5 0

2 years ago

What are the solutions to the quadratic equation (5y + 6)2 = 24?b

Fofino [41]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers