Explanation:
Value of the cross-sectional area is as follows.
A =
= 3.45
The given data is as follows.
Allowable stress = 14,500 psi
Shear stress = 7100 psi
Now, we will calculate maximum load from allowable stress as follows.
=
= 50025 lb
Now, maximum load from shear stress is as follows.
=
= 48990 lb
Hence, will be calculated as follows.
= 48990 lb
Thus, we can conclude that the maximum permissible load is 48990 lb.
Answer:
Meters
Explanation:"How FAR did the athlete run?"
Also it talked about meters
Answer:
yes
Explanation:
because when you slow down, the resistance slows with the speed.
To find the slope of a line:
-- pick 2 points on the line
-- find the change in 'y' as the line goes from one point to the other
-- find the change in 'x' as the line goes from one point to the other
-- divide (the change in y) by (the change in x).
-- the quotient is the slope.
This is exactly the fraction in the picture, starting with "m = ".
For the line in the picture, let's take the starting point and the ending point.
-- the change in 'y' from beginning to end is 20 meters .
-- the change in 'x' from beginning to end is 5 seconds .
-- The slope is
(20 meters) divided by (5 seconds)
= (20 / 5) (meters/seconds)
= 4 meters per second .
Add the KE increase and the work done against friction.
The final velocity is twice the average, or 3.0 m/s
The final KE is (1/2)*25*3^2 = 112.5 J
The friction work done is 6*3.8 = 22.8 J
hope this is correct