Question

The position of a particle moving along the x axis is given by x = (21 + 22t – 6 t2) m, where t is in s. What is the average velocity during the time interval t = 1 s to t = 4 s?

Answer 1

Answer:

12m/s

Explanation:

x = (21 + 22t – 6 t2) m,

We can express change bin velocity as

dx/dt= -12t + 22

But Velocity is changing

interval t = 1 s

t = 4 s

at t = 1, x = 21 + 22(1) -6(1)^2

=37

at t = 4, x = 21 + 22(4) -6(4)^2

=13

Distance travelled at interval t = 1 s

t = 4 s

X2 - X1=13- 37. = - 24m

Velocity= displacement/ time

= 24/(3-1)=12 m/s