Answer:
F = 2,894 N
Explanation:
For this exercise let's use Newton's second law
F = m a
The acceleration is centripetal
a = v² / r
Angular and linear variables are related.
v = w r
Let's replace
F = m w² r
The radius r and the length of the rope is related
cos is = r / L
r = L cos tea
Let's replace
F = m w² L cos θ
Let's reduce the magnitudes to the SI system
m = 101.7 g (1 kg / 1000g) = 0.1017 kg
θ = 5 rev (2π rad / rev) = 31,416 rad
w = θ / t
w = 31.416 / 5.1
w = 6.16 rad / s
F = 0.1017 6.16² 0.75 cos θ
F = 2,894 cos θ
The maximum value of F is for θ equal to zero
F = 2,894 N
Answer:
150J
Explanation:
work output/work input=100%
so just make work output the subject
The momentum of truck is 20790 kg m/s
<em><u>Solution:</u></em>
Given that we have to find the momentum of truck
From given, 1155 kg truck has a velocity of 18 m/s
Therefore,
Mass = 1155 kg
Velocity = 18 m/s
<em><u>The momentum is given by formula:</u></em>
Where, m is mass in kg and v is velocity in m/s
Substituting the values we get,
Thus momentum of truck is 20790 kg m/s
Answer:
Scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a hypothesis.
Explanation:
very interesting and amazing question u had asked but i get it...
Answer
W = Force × Displacement
- but in above case force is exerted on the men as the weight of the child × gravitational pull of earth (9.8 m/s^2) but the displacement or movement is ZERO
- there for W= F×0 =0
- so even after carrying child for 2 hours work done by the men will be zero
<u>More</u><u> </u><u>examples</u>
- a person standing straight and lifting weight
- a person carry some weight and walk in a circular path and came back to its original position.........in this case also Displacement will be zero
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hope it helped u buddy
