Tamu ran 30 minutes and burned 170 calories.

Which point is a reflection of T(-6.5, 1) across the x-axis and the y-axis?

drek231 [11]

First, start off with the x-axis. -6.5, 1 becomes 6.5, 1. This is because point T is 6.5 to the left of the x-axis line, so our new point would be 6.5 to the right of the x-axis line. Same thing for the y-axis, (6.5, 1) would become (6.5, -1).

8 0

3 years ago

C= 6x+100 and c=10x+80 <br> what number does x have to be for c to be the same on each equation?

slega [8]

Answer:

x= 5 , for c to be same on each eqn

7 0

2 years ago

A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has

bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] = 1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0

3 years ago

15.What must be subtracted from x 3 + 3x-8 to 2x 3 +x 2 -4x+2

Alik [6]

Answer:

Step-by-step explanation:

2 x 3−3 x 2+ x −30=0 ... The groups have no common factor and can not be added up to form a multiplication. Polynomial Roots Calculator : 3.3 Find roots (zeroes) of : F(x) = 2x3-3x2+x-30 ... Subtract 5 from both side of the equation : ... abc. a. x. y. /. |abs|. ( ). 7. 8. 9. *. 4. 5. 6. -. %. 1. 2. 3. +. <. > 0. , . = abc. a. b. c. d. e.

8 0

3 years ago

Someone help me out with this

anygoal [31]

Answer: x = 10

Explanation: The bottom left angle is 90 degrees because of the symbol. ( Make sure you know this for future problems.) The whole triangle needs to add up to 180. This isn’t the right way to solve this kind of problem but I know how to solve it using this way and I know the at 10 is the right answer. The other two angles need to add up to 90 because 90 + 90 = 180. So basically I just substituted the same number into x until I added both outcomes and got 90. I hope you understand that cause I don’t really know how to explain it well. Let me try and show you.

3(x)+5 6(x)-5

Now you have to plug in the same number for x until both numbers add to ninety.

3(5)+5 6(5)-5.

( 5 isn’t the right number for x this is just an example. )

You end up with 20 for the first one, and 25 for the second one. 20 + 25 = 45 and 90 + 45 is only 135. So this means that 5 isn’t the right answer and you need to substitute a higher number in for x.

3(10)+5 6(10)-5

( This is the right setup. )

You end up with 35 for the first one and 55 for the second one after you distribute and solve. Now you have 35 and 55. 35 + 55 = 90 and 90 + 90 = 180. This is how you know that you are right. I hope this helps. :)

8 0

3 years ago