You are wrapping a birthday gift that is packaged in a specially made pyramid-shaped box. The base of the box measures 10 inches
by 9 inches and the slant height is 6 inches. How much paper do you need to wrap the box
1 answer:
Answer:
2826 inches^2
Step-by-step explanation:
The general formula for the total surface area of a regular pyramid is
T.S.A.=12pl+B
Where p represents the perimeter of the base, l the slant height and B the area of the base.
The perimeter of the base is.
p=2L+2W
P=2*10+2*9
P=20+18
P= 38 inches
The area of the base is.
B=10*9
B=90in^2
T.S.A.=12(38)(6)+90
T.S.A=2736+90
T.S.A=2826 inches^2
Hence the paper needed is 2826 inches^2
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