The conditions are suitable to be modelled using a binomial distribution.
p=0.43
n=15
x=5
P(x=5)
=C(15,5)*0.43^5*(1-0.43)^(15-5)
=15!/(5!(15-5)!)*0.43^5*(1-0.43)^(15-5)
=3003*0.0147008*0.003620333
=0.1598
Answer:
3.) What a person does is more important than what they say they will do.
Step-by-step explanation:
1.75=12.3-x/2.8
x=(12.3-1.75)2.8
x=29.54
<span>The answers are (-3, -2) (–1, –2) (1, –2) (1, 2).
Let's check out all of the possible solutions.
(-3, -2).
x = -3; y = -2.
y < 0.5x + 2;
-2 < 0.5 * (-3) + 2;
-2 < -1.5 + 2;
-2 < 0.5.
This is correct.
(-2, 1).
x = -2; y = 1.
y < 0.5x + 2;
1 < 0.5 * (-2) + 2;
1 < -1 + 2;
1 < -1.
This is not correct.
(-1, -2).
x = -1; y = -2.
y < 0.5x + 2;
-2 < 0.5 * (-1) + 2;
-2 < -0.5 + 2;
-2 < 1.5.
This is correct.
(-1, 2).
x = -1; y = 2.
y < 0.5x + 2;
2 < 0.5 * (-1) + 2;
2 < -0.5 + 2;
2 < 1.5.
This is not correct.
(1, -2).
x = 1; y = -2.
y < 0.5x + 2;
-2 < 0.5 * (1) + 2;
-2 < 0.5 + 2;
-2 < 2.5.
This is correct.
(1, 2).
x = 1; y = 2.
y < 0.5x + 2;
2 < 0.5 * (1) + 2;
2 < 0.5 + 2;
2 < 2.5.
This is correct.</span>
Answer:
The length of the string is 32.56 feet (Approx) .
Step-by-step explanation:
As given
A kite is 37 feet in the air and string forms an angle of 62 degrees .
Now by using the trignometric identity.
As shown in the figure given below.
Perpendicular = AB
Hypotenuse = AC = 37 feet
Put in the identity .
Put in the identity
AB = 0.88 × 37
AB = 32.56 feet (Approx)
Therefore the length of the string is 32.56 feet (Approx) .