To get the coordinates of C we shall proceed as follows:
AB:BC=1:4
B-A=[(-3--7),(-5--8)]=(4,3)
4(4,3)=(16,12)
thus the coordinates of C will be:
(16-3,-5+12)
=(13,7)
Answer:
18
Step-by-step explanation:
Given the data:
180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg
The interquartile range (IQR) = Q3 - Q1
Reordering the data:
180, 188, 190, 192, 195, 200, 205, 209, 250
Q3 = 3/4(n+1)th term
Q3 = 3/4(10) = 7.5 th term = (205+209)/2 = 207
Q1 = 1/4(n+1)th term
Q1 = 1/4(10) = 2.5th term = (188+190)/2 = 189
Q3 - Q1 = 207 - 189 = 18
Answer:
B. -10
Step-by-step explanation:
The first one has got a result different from -12 or -10
Answer:
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps
