A bear has a mass of

Two arithmetic means between 3 and 24 are -

defon

The value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.

<h3>What is arithmetic mean?</h3>

Arithmetic mean is the mean or average which is equal to the ratio of sum of all the group numbers to the total numbers.

The two arithmetic means between 3 and 24 are has to be inserted.

3, A₂, A₃, 24

All the four numbers are in arithmetic progression. The nth terms of AM can be found using the following formula:

t(n)=a(n-1)d

Here, d is the common difference a is the first terms and n is the total term. The first term, a=3 and t₄=24. Thus, the common difference is;

$t(n)=a(n-1)d\\t(4)=3(4-1)d\\24=3(3)d\\24=9d\\d=\dfrac{24}{9}$

The second and 3rd term are:

$A₂=3+\dfrac{24}{9}=\dfrac{51}{9}\\ A₃=\dfrac{51}{9}+\dfrac{24}{9}=\dfrac{75}{9}$

Thus, the value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.

Learn more about the arithmetic mean here;

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8 0

1 year ago

The function N(X) = 90(0.86)* + 69 can be used to predict the temperature of a

dezoksy [38]

Answer: -8.93

Step-by-step explanation:

Given the function:

N(X) = 90(0.86)^x+ 69

X in the interval [0, 6]

For X = 0

N(0) = 90(0.86)^0 + 69

90 + 69 = 159

For X = 6

N(6) = 90(0.86)^6 + 69

90(0.404567235136) + 69

= 105.41105116224

Therefore, average change of change in temperature ;

(temp 2 - temp 1) / ( time 2 - time)

(105.41105116224 - 159) / (6 - 0)

= - 53.58894883776 / 6

= - 8.93149147296

= - 8.93

4 0

2 years ago

Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V) = 0.17

ArbitrLikvidat [17]

Answer: 0.82

Step-by-step explanation:

The probability of the computer not containing neither a virus nor a worm is expressed as P( $V^{C}$ ∩ $W^{C}$ ) , where P( $V^{C}$ ) is the probability that the event V doesn't happen and P( $W^{C}$ ) is the probability that the event W doesn't happen.

P( $V^{C}$ )= 1-P(V) = 1-0.17 = 0.83

P( $W^{C}$ )=1-P(W) = 1-0.05 = 0.95

Since $V^{C}$ and $W^{C}$ aren't mutually exclusive events, then:

P( $V^{C}$ ∪ $W^{C}$ ) = P( $V^{C}$ ) + P( $W^{C}$ ) - P( $V^{C}$ ∩ $W^{C}$ )

Isolating the probability that interests us:

P( $V^{C}$ ∩ $W^{C}$ )= P( $V^{C}$ ) + P( $W^{C}$ ) - P( $V^{C}$ ∪ $W^{C}$ )

Where P( $V^{C}$ ∪ $W^{C}$ ) = 1 - 0.04 = 0.96

Finally:

P( $V^{C}$ ∩ $W^{C}$ ) = 0.83 + 0.95 - 0.96 = 0.82

5 0

2 years ago

I don't know this. (3)

Dahasolnce [82]

Answer:

16 feet

Step-by-step explanation:

add 10 ft & 6 ft

3 0

2 years ago

3(8 - 4x) = 12<br><br> Please help. You have to use distributive property to solve.

____ [38]

Answer:

x=1

Step-by-step explanation:

First, we distribute the 3 to the 8 and the 4x.

Now we have 24-12x=12

Then, we subtract 24 from 12

Now we have -12x=-12

Finally, we devide -12 by -12

Now we have x=1

Hope that helps!

8 0

2 years ago