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3 years ago

There is a 15% discount on all items in a store. You buy a $12 shirt and $45 jeans. What will be your total cost?

Mathematics

2 answers:

Nina [5.8K]3 years ago

6 0

Answer:

The total cost of the shirt and Jean's together with a 15% discount would be $48.45.

Step-by-step explanation:

if you at 12 and 45 you get 57 now if you multiply that by .15 which would be 15% you would get $48.45.

TEA [102]3 years ago

3 0

Answer:

$48.45

Step-by-step explanation:

15% of $12= 1.80

15% of $45= 6.75

$12-$1.80= $10.2

$45- $6.75= $38.25

Now, add them both up:

$10.20+ $38.25= 48.45

Answer= $48.45

Hope it helps,

PS- Please mark me as brainliest :)

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2 years ago

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A Poker club has 10 members. A president and a vice-president are to be selected. In how many ways can this be done if everyone

Nesterboy [21]

Answer:

90 different ways

Step-by-step explanation:

We have a total of 10 members, and we want to find how many groups of 2 members we can have, where the order of each member in the group of 2 is important, so we have a permutation problem.

To solve this problem, we need to calculate a permutation of 10 choose 2.

The formula for a permutation of n choose p is:

$P(n, p) = n! / (n - p)!$

So we have:

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3 years ago

5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?

Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

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2 years ago