Significant figures are the digits that carry meaning to its measurement. Significant figures includes all the numbers excluding all the leading zeros, trailing zeros. All non zero digits are significant. Zeros between the non zero digits are significant. In a decimal number, trailing zeros are significant.
Now, consider the given number 0.23350
Since, in a decimal number all the trailing zeros are significant.
So, in the number 0.23350 there are five significant figures 2,3,4,5 and 0.
Therefore, there are 5 significant figures in the given number.
Answer:
-5(2) (-2) +2 + 4(-2) +7 = 21
-4(2) -2(-2) -10 = -14
21/14 = -1.5 or -1 1/2
Step-by-step explanation:
I think 160! I don't know it true or not
The probability that a randomly selected man dies of cancer during the course of the year =

The probability that a randomly selected man does not die of cancer during the course of the year =

The probability that atleast one man of this age dies of cancer is the complement of the probability that no man dies of cancer. In equation form we can write:
Probability that atleast one man of this age dies of cancer = 1 - No man at this age dies of cancer
The probability that no man dies of cancer out of 1000 selected men =

, rounded of to 5 decimal places
Thus the probability that atleast one man at this age dies of cancer = 1 - 0.04956 = 0.95044