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Rom4ik [11]
4 years ago
8

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

ate of increase or decrease. y=570(0.98)^x
Mathematics
1 answer:
oee [108]4 years ago
8 0

Answer:

  • decay
  • 2% decrease

Step-by-step explanation:

The growth factor is the base of the exponent: 0.98. Its relation to the rate of change is ...

  growth factor = 1 + rate of change

  0.98 = 1 + (-0.02)

So, the rate of change is -0.02 = -2%. Since the rate of change is a 2% decrease, it represents decay.

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Find the coordinates if the midpoint of a line segment with endpoints (-3,4) and (7,9).
svetoff [14.1K]
Using the midpoint formula 
\frac{ x_{1}+ x_{2}  }{2},  
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\frac{-3+7}{2},
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\frac{4}{2},
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(2,6.5)
So, your answer would be (2,6.5).
5 0
3 years ago
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Please answer this correctly
brilliants [131]

Answer:

3 years 8 month

Step-by-step explanation:

Given 7 years 6 months - 3 years 10 months

Step 1: Firstly we should subtract months from months then after from year to year.

Step 2: 6 months is less than 10 months so we have to borrow 1 year and add it to the months.

Step 3: Adding 1 year to 6 months we get 18 months.

Step 4: Now we have to subtract 3 years 10 months from 6 years 18 months.

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8 0
3 years ago
URGENT PLEASE HELP! What is the slope of the line <br> y = -2x - 4?
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Step-by-step explanation:

4 0
3 years ago
I<br> For what value of y does 125
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Step-by-step explanation:

7 0
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ipn [44]

\dfrac{x-1}{x}=5\ \ \ \ /x\neq0\\\\\dfrac{x-1}{x}=\dfrac{5}{1}\ \ \ \ |\text{cross multiply}\\\\5x=x-1\ \ \ \ |-x\\\\5x=1\ \ \ \ |:5\\\\x=0.2\\\\\dfrac{x^3+1}{x^3}=\dfrac{x^3}{x^3}+\dfrac{1}{x^3}=1+\dfrac{1}{x^3}\to1+\dfrac{1}{0.2^3}=1+\dfrac{1}{0.008}\\\\=1+\dfrac{1}{\frac{8}{1,000}}=1+\dfrac{1,000}{8}=1+125=126\\\\\text{Answer:}\ \dfrac{x^3+1}{x^3}=126

5 0
4 years ago
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