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2 years ago

Can someone answer it thankyou:-) :-)

Mathematics

1 answer:

NikAS [45]2 years ago

5 0

That's all the answers and the work and i also put the PEMDAS method that i used.

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Please help me solve this whole problem!

kondor19780726 [428]

Answer:

(0, -4)

rise/run = (-5/1)

x y

1 -9

2 -14

3 -19

4 -24

5 -29

6 -34

Step-by-step explanation:

You're going to have to graph it yourself.

Take the coordinated and just plot the points, then draw the line.

(1,-9)

(2,-14)

(3,-19)

(4,-24)

(5,-29)

(6,-34)

3 0

2 years ago

5+2b-2 =( )b+( ) please i need help!!!!

strojnjashka [21]

Answer:

Step-by-step explanation: sorry im stuck too :(

4 0

2 years ago

What is the volume of this rectangular prism?

sergiy2304 [10]

Answer:

$V =\frac{12}{5}\ cm^3$

Step-by-step explanation:

The Volume of Rectangular Prism

Given a rectangular prism of dimensions W, L, and H, its volume is the product of the three dimensions:

V = WLH

The figure shows the dimensions:

L=3 cm

$W=\frac{4}{3}\ cm$

$H=\frac{3}{5}\ cm$

Thus, the volume is:

$V =3*\frac{4}{3}*\frac{3}{5}\ cm^3$

$V =\frac{36}{15}\ cm^3$

Simplifying:

$\boxed{V =\frac{12}{5}\ cm^3}$

5 0

2 years ago

State which of the following sets of ordered pairs represents a function. Please pick the best option

IRINA_888 [86]

Answer:

set A and set B...it is the best and right option bro...option c is wrong because 2 elements of domain has relation with 1 range

3 0

3 years ago

In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence

Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of z for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0

2 years ago