Can someone answer it thankyou:-) :-)
1 answer:
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Minor Arc AC = 110 degrees (given)
As indicated in the hints,
OA=OC => OAC=OCA=(180-110)/2 = 35
Similarly,
OAB=OBA=(48-35)=13
=>
OBC=OCB=(180-35-35-13-13)/2=(180-96)/2=84/2=42
=>
Angle B = 13+42 = 55 degrees
Check:
55+55+35+35+13+13 = 180 degrees (angles of a triangle) ok.
As indicated in the hints,
OA=OC => OAC=OCA=(180-110)/2 = 35
Similarly,
OAB=OBA=(48-35)=13
=>
OBC=OCB=(180-35-35-13-13)/2=(180-96)/2=84/2=42
=>
Angle B = 13+42 = 55 degrees
Check:
55+55+35+35+13+13 = 180 degrees (angles of a triangle) ok.
Answer:
(x,y) = Any point on the line
m = the slope of the line
(x₁, y₁) = A given point on the line
Step-by-step explanation:
the equation of a straight line is;
y = mx + c
where;
x and y are any point on the line
m is the slope of the line
c is the intercept on the y axis
And a given point on (x,y) can be written as (x₁, y₁)
Therefore, for the case above;
(x,y) = Any point on the line
m = the slope of the line
(x₁, y₁) = A given point on the line
