Question

What is the force two changed objects exert on one another if they are 9 meters apart and one has a charge of 2.5 x 10^-6 C and the second has a charge 0f 4.5 x 10^-7 C

Answer 1

Answer:

The force exerted between the two charges is 0.0001248N

Explanation:

we will be using Columb's law to solve this problem.

Columb's law explains that the Force between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Mathematically,

$F = K\frac{Q_1 \times Q_2}{r^2}$

WHere K = constant of proportionality = $8.9875 \times 10^9 N m^2/c^2$

$F = 8.9875 \times 10^9 \times\frac{2.5 \times10^{-6} \times 4.5 \times 10^{-7}}{9^2}= 0.0001248N$

The force exerted between the two charges is 0.0001248N