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3 years ago

While planets are smaller than stars, planets are generally larger than which of the following?

Physics

2 answers:

wel3 years ago

6 0

Answer:

The other bodies in a solar system

Explanation:

Stars are generally bigger in size than the objects orbiting around them. Star is the object that holds all the object of a star system in a definite shape and makes all the objects orbit it due to its gravity. Of all these objects few are designated as planets as per the criteria laid down by the International Astronomical Union (IAU). One of the criteria is: "The planets orbit around the star and clear their orbit i.e. they are the biggest object in that region".

By this logic it is pretty evident that they are bigger than other objects in the star system (or in our case the solar system).

Sauron [17]3 years ago

3 0

the answer was B

hope that helps you

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To maintain a constant speed, the force provided by a car's engine must equal the drag force plus the force of friction of the r

sweet [91]

Answer:

a). 53.75 N and 101.92 N

b). 381.44 N and 723.25 N

Explanation:

$V= 77 \frac{km}{h}* \frac{1h}{3600 s} *\frac{1000m}{1 km} = 21.38 \frac{m}{s} \\V=106 \frac{km}{h}* \frac{1h}{3600 s} *\frac{1000m}{1 km} = 29.44 \frac{m}{s}$

a).

ρ $= 1.2 \frac{kg}{m^{3} }$ , $A_{t}= 0.7 m^{2}$ , $D_{t}= 0.28$

$F_{t1} = \frac{1}{2} * D_{t} * A_{t}* p_{t}* v_{t}^{2}$

$F_{t1} = \frac{1}{2} * 0.28 * 0.7m^{2} * 1.2\frac{kg}{m^{3} }* 21.38^{2}= 53.75 N$

$F_{t1} = \frac{1}{2} * 0.28 * 0.7m^{2} * 1.2\frac{kg}{m^{3} }* 29.44^{2}= 101.92 N$

b).

ρ $= 1.2 \frac{kg}{m^{3} }$ , $A_{h}= 2.44 m^{2}$ , $D_{h}= 0.57$

$F_{t1} = \frac{1}{2} * D_{h} * A_{h}* p_{h}* v_{h}^{2}$

$F_{t1} = \frac{1}{2} * 0.57 * 2.44 m^{2} * 1.2\frac{kg}{m^{3} }* 21.38^{2}= 381.44 N$

$F_{t1} = \frac{1}{2} * 0.57 * 2.44 m^{2} * 1.2\frac{kg}{m^{3} }* 29.44^{2}= 723.25 N$

6 0

3 years ago

To calculate work done on an object, _____. A. multiply the force in the direction of motion by the distance the object moved B.

o-na [289]

I believe your answer would be B, hope it helps

6 0

3 years ago

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Vector A has components Ax=1.30cm, Ay= 2.25cm; vector B has components Bx=4.10cm, By=-3.75cm.

geniusboy [140]

We are given with the x and y components of Vector A and B. In this case, we compute the resultant of both components of each vector. The vector is equal to the square root of the sum of the squares of the components. A is equal to 2.60 cm. B is equal to 5.56 cm. B is found in quadrant Iv and has an angle of 42.447 degrees as a terminal angle. A has an angle of 59.98 degrees.
a. 5.6082 < -15.53 degreesc. 6.63 <-64.98 degreesb. x = 6.63 cos -64.98 degrees = 2.80 y = 6.63 sin -64.98 degrees = -6.00

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3 years ago

The first thing that made Trestail curious about the Crippen case was that __________.

Anna35 [415]

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7 0

3 years ago

Can someone help me answer this pls I’ll give brainliest

hammer [34]

Answer: I think the answer is Non-foliated if it is wrong i am so sorry

don't forget to drop a heart.

Explanation:

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3 years ago