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netineya [11]
4 years ago
15

A 900 kilogram compact car was stopped at a traffic light when an 1800 kilogram luxury sedan struck it from behind the two cars

became entangled due to conclusion is a luxury sedan was traveling at a velocity of 34.0 m/s North before the Collision what is the velocity of entangled Mass after the collison
A. 11.6 kg-m/s
B. 22.7 kg-m/s
C. 33.8 kg-m/s
D. 44.9 kg-m/s
Physics
1 answer:
SOVA2 [1]4 years ago
7 0
The answer is B. 22.7 kg-m/s
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After all, "Spring Tides" (peak ocean tides that arise bi-monthly) occur when the Sun, the Moon and the Earth are nearly in a straight line around the times of the New Moon and Full Moon.

Explanation:

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4 years ago
Two life preservers have identical volumes, but one is filled with Styrofoam while the other is filled with sand. When the two l
soldier1979 [14.2K]

Answer:

Sand

Explanation:

While the term buoyancy may confuse the reader, the question here is referring to buoyant force.

Buoyant force is the amount of pressure exerted on an object by the liquid it is in. Given by the formula

F_{b} = V_{o} D_{l} g

Where

F_{b} = Buoyant Force

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Since in this question the swimmer with the sand is completely submerged in water, more of the volume of his preserver is under the water hence the buoyant force is greater on it than the swimmer with the Styrofoam (as part of him is not submerged in water)

6 0
3 years ago
A car is moving in the positive direction along a straight highway and accelerates at a constant rate while going from point A t
rusak2 [61]

Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

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v(t) = v0 + at

Where v0 is the initial speed and a is the constant acceleration.

Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:

v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt

v_ave = v0+a(T/2)

We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>

v(T/2)=v_ave

Now we want to know where the car should be, the osition of the car is:

x(t) = x_A + v_0 t + \frac{1}{2}at^2

Where x_A is the position of point A. Therefore, the car will be at:

<u><em>x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2</em></u>

8 0
3 years ago
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raketka [301]
A=(vf-v₀)/t

Data:
vf=100 m/s
v₀=70 m/s
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a=(100 m/s - 70 m/s)/1.5 s=30 m/s / 1.5 s=20 m/s².

answer:  C. 20 m/s²
3 0
3 years ago
Define mechanics.
SOVA2 [1]

Answer:

The branch of applied mathematics dealing with motion and forces producing motion is called mechanics.

3 0
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