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netineya [11]
3 years ago
15

A 900 kilogram compact car was stopped at a traffic light when an 1800 kilogram luxury sedan struck it from behind the two cars

became entangled due to conclusion is a luxury sedan was traveling at a velocity of 34.0 m/s North before the Collision what is the velocity of entangled Mass after the collison
A. 11.6 kg-m/s
B. 22.7 kg-m/s
C. 33.8 kg-m/s
D. 44.9 kg-m/s
Physics
1 answer:
SOVA2 [1]3 years ago
7 0
The answer is B. 22.7 kg-m/s
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Velocity, as it is is a vector quantity, so it has both direction and magnitude.
Speed is a scalar quantity, so it only has magnitude, no direction.
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3 years ago
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Which describes a reflected image in a plane mirror?
Paul [167]

Answer:

B. The image is right-left reversed and about as far away from the mirror as the reflected object.

Explanation:

A plane mirror is used in several ways in our life, from the mirror that we have on the bathroom to the mirrors we use on cars, the main difference is that the mirror reflects the image reversed on the Vertical axis, which means that the left is the right and the right is the left, a mirror also protrays objects at a certain distance, about as far away from the mirror as the reflected object but they are actually closer in real life.

4 0
3 years ago
A single slit forms a diffraction pattern, with the first minimum at an angle of 40.0° from central maximum, when monochromatic
Margarita [4]

Answer:

\lambda = 424.4 nm

Explanation:

As we know by the formula of diffraction

a sin\theta = N\lambda

so we have

a = slit size

\theta = angular position of Nth minimum

so we will have

for first minimum of 630 nm light

a sin40 = 1(630 \times 10^{-9})

a = 9.8 \times 10^{-7} m

Now for another wavelength second minimum is at 60 degree angle

a sin60 = 2 \lambda

(9.8 \times 10^{-7}) sin60 = 2 \lambda

\lambda = 424.4 nm

3 0
3 years ago
A pump lifts 400 kg of water per hour a height of 4.5 m .
nasty-shy [4]

Answer:

Power = Work / Time

P = 400 kg * 9.8 m/s * 4.5 m / 3600 sec = 4.9 J/s = 4.9 Watts

Also, 4.9 Watts / (746 Watts / Horsepower) = .0066 Hp

6 0
2 years ago
A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
maksim [4K]

Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

  The first amplitude of the wave is  E_{max}1 =  98.02 \  V/m

  The first  depth  is  D_1 =  10 \  m

   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

   The second depth is D_2 = 100 \ m

Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

=>   \alpha  =  \frac{0.18}{90}

=>    \alpha =  0.002 Np/m

       

4 0
3 years ago
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