Answer:
0.027
Step-by-step explanation:
0.1×0.1×0.1=0.027----->2.7×10^-2
If it’s a right triangle 1 side is a right angle and if those 2 sides are equal and not right angles then E needs to be a right angle and a right angle is 90 degrees so it’s D
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
17/7
Step-by-step explanation:
2g+2(-8+2g)=1-g
2g-16+4g=1-g
6g-16=1-g
6g-(-g)-16=1
6g+g=1+16
7g=17
g=17/7
Answer:
(7w - k)(4x + y)
Step-by-step explanation:
Factor by grouping is best for this expression. To factor by grouping, group pairs of terms with parenthesis. Then find the GCF in each pair. If the parenthesis match after, the factoring is complete.
28xw + 7wy - 4kx - ky
(28xw + 7wy) + (- 4kx - ky)
7w(4x + y) - k (4x + y)
The factors are (7w - k)(4x + y).