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3 years ago

Which of the following shapes are rhombuses? Choose 2 answers !!!!!! Please helppp !!!!!!!!!!! Will

Mathematics

2 answers:

Elina [12.6K]3 years ago

5 0

B and C is the answer if you look at them closely.

vodomira [7]3 years ago

4 0

Answer:

C and D are rhombuses

Step-by-step explanation:

C is a rhombus because the shape is a parallelogram with all equal sides. And if the sides are all equal in a parallelogram then it is a rhombus.

D is also a rhombus because the shape is a square with equal sides and with right angles. Furthermore, a square is always a rhombus because of the sides and the right angle.

So the final answer is C and D.

Hope it helped!

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tigry1 [53]

Answer:

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4 years ago

Brenda has a square-shaped photo frame. If the area of the square frame is 123 square inches, which statement is true?

Sergeu [11.5K]

The length equals √123=11.09 inches
Therefore the statement "The length of the photo frame is between the 11 inches and 12 inches." is true.

4 0

3 years ago

Rewrite 4 as an improper fraction.

algol13

Here 4/3, 11/4, or 7/7
I hope this helps

8 0

3 years ago

Read 2 more answers

What is the value of n such that the expression x² + 11x + n is a perfect square trinomial? a. 11. b. 25. c. 30. d.25. e.36

lapo4ka [179]

Answer:

The value of n is 30.25.

Step-by-step explanation:

The given expression is

$x^2+11x+n$ ....(1)

The perfect square trinomial are defined as

$(x+y)^2=x^2+2xy+y^2$ .....(2)

On comparing (1) and (2), we get

$2y=11$

$y=\frac{11}{2}$

The given expression is perfect square trinomial if

$n=y^2$

$n=(\frac{11}{2})^2$

$n=\frac{121}{4}$

$n=30.25$

Therefore the value of n is 30.25.

5 0

3 years ago

Read 2 more answers

Midpoint Formula:

Sedaia [141]

The coordinates of the midpoint of the segment joining the two points (0, 2) and (6, 4) is (3, 3)

<h3>Solution:</h3>

Given that two points are (0, 2) and (6, 4)

To find: coordinates of the midpoint of the segment joining the two points

The midpoint of line joining two points is given as:

For a line containing two points $(x_1, y_1)$ and $(x_2, y_2)$

$\text {Midpoint}(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

In the given sum, two points are (0, 2) and (6, 4)

$x_{1}=0 ; y_{1}=2 ; x_{2}=6 ; y_{2}=4$

Substituting the values in given formula,

$\begin{array}{l}{\text {Midpoint}(x, y)=\left(\frac{0+6}{2}, \frac{2+4}{2}\right)} \\\\ {\text {Midpoint }(x, y)=\left(\frac{6}{2}, \frac{6}{2}\right)=(3,3)}\end{array}$

Thus the required midpoint is (3, 3)

8 0

3 years ago