Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
Answer:
C
Step-by-step explanation:
-4+9=5
Given:
Consider the given expression is

To find:
The simplified form of the given expression.
Solution:
We have,

Using properties of exponents, we get
![[\because a^ma^n=a^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5Ema%5En%3Da%5E%7Bm%2Bn%7D%5D)




Therefore, the simplified form of given expression is 25.
3x10^8 is 7 times larger than 3x10^2
Answer:
x = 43.7°
Step-by-step explanation:
Reference angle (θ) = x°
Opposite side length = 43
Adjacent side length = 45
Apply the trigonometric function, TOA, which is:
Tan θ = Opp/Adj
Substitute


x = 43.7° (nearesth tenth)