13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
<u>Step-by-step explanation:</u>
Total mass of acid required= 85 ounces
Let the mass of 72% acid be 'a'
Let the mass of 25% acid be 'b'
a + b = 85
b = 85-a
85(40/100) = a(72/100) + b(25/100)
85(2/5) = a(72/100) +(85- a) (25/100)
34 = (72a/100) + (2125/100) - (25a/100)
34 - (2125/100) = (72a + 25a) /100
(3400-2125)/100 = 97a /100
97a = 1275
a = 13.15 ounces
b = 85 - 13.14
b = 71.85 ounces
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
The sum of all the measurements is just the average times the number.
So if the average of all 92 is 7 the sum of those is
The average of the last two is 7.2 so their sum is
That means the sum of the first 90 is
so the average of the first 90 is
cm
Is C g(x) = -X^2 -3
This is the answer
Answer:
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Step-by-step explanation:
I took the quiz :)
Answer:
Step-by-step explanation:
Set up proportions. Make sure length and widths line up!
Then do butterfly method.
Solve for x.
Hope that helped!