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inessss [21]
3 years ago
11

your friend claims that two isosceles triangles ABC and DEF are congruent if two corresponding sides are congruent. he explains

that there are only two different lengths of sides , so if AB is congruent to DE and BC us congruent to EF, then it must follow that CA is congruent to FD. explain the error in his reasoning
Mathematics
1 answer:
Svetach [21]3 years ago
7 0
Think about the fact that you can have two types of isosceles triangle: one of them that is a right triangle (isosceles right triangle) such as a 45-45-90 triangle and the other type can be just a regular triangle that has two sides that are congruent but it isn't a right triangle. 

Thus, you would need more info about the triangles in order to conclude that the two isosceles triangles are congruent to each other. 
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Answer:

144

Step-by-step explanation:

Length of 1 side is 12 so area is 12*12

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Answer:

\large Q1:\ x=18\ ft\\\\Q2:\ 6\ inches

Step-by-step explanation:

Q3.

If ΔGHI and ΔJKL are similar, then the sides are in proportion:

\dfrac{JL}{GI}=\dfrac{LK}{IH}

We have

JL = x, GI = 9 ft, LK = 24 ft, IH = 12 ft.

Substitute:

\dfrac{x}{9}=\dfrac{24}{12}

\dfrac{x}{9}=2         <em> multiply both sides by 2</em>

x=18\ ft

Q4.

We must multiply the original length by a scale factor of 3/4:

\dfrac{3}{4}\cdot8\ in=\dfrac{3}{1}\cdot2\ in=(3)(2)\ in=6\ in

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3 years ago
A random sample of 16 students selected from the student body of a large university had an average age of 25 years. We want to d
kenny6666 [7]

Answer:

z=\frac{25-24}{\frac{2}{\sqrt{16}}}=2    

p_v =2*P(Z>2)=0.0455  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean differs from 24 at 5% of significance

Step-by-step explanation:

Data given and notation  

\bar X=25 represent the sample mean

\sigma=2 represent the sample population deviation for the sample  

n=16 sample size  

\mu_o =24 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 24, the system of hypothesis would be:  

Null hypothesis:\mu = 24  

Alternative hypothesis:\mu \neq 24  

If we analyze the size for the sample is < 30 but we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{25-24}{\frac{2}{\sqrt{16}}}=2    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(Z>2)=0.0455  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean differs from 24 at 5% of significance

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The answer is c 19
38/2=19
Step-by-step explanation
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