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inessss [21]
3 years ago
11

your friend claims that two isosceles triangles ABC and DEF are congruent if two corresponding sides are congruent. he explains

that there are only two different lengths of sides , so if AB is congruent to DE and BC us congruent to EF, then it must follow that CA is congruent to FD. explain the error in his reasoning
Mathematics
1 answer:
Svetach [21]3 years ago
7 0
Think about the fact that you can have two types of isosceles triangle: one of them that is a right triangle (isosceles right triangle) such as a 45-45-90 triangle and the other type can be just a regular triangle that has two sides that are congruent but it isn't a right triangle. 

Thus, you would need more info about the triangles in order to conclude that the two isosceles triangles are congruent to each other. 
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the area of a rectangle is x²-3x-10. what is the length of the rectangle if the with is x +2.?plsss asap​
Inga [223]

Answer:

x - 5

Step-by-step explanation:

x^2 - 3x - 10

= (x + 2)(x - 5)

Sine the width is (x + 2), the length is (x - 5).

Hope this helped!

7 0
3 years ago
Mrs. Lynch has noted that 7 out of every 10 pieces of mail she gets are junk mail. What percent of her mail is junk?
ikadub [295]
The answer to this question is 70%
6 0
2 years ago
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I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

First Mistake : Line 2

a = x \\ b = 6 \\ c = 10

Second Mistake : Line 4

136 =  {x}^{2}  \\ not \\ 136 = x

Correct Solution :

{x}^{2}  +  {6}^{2}  =  {10}^{2}  \\  {x}^{2}  =  {10}^{2}  -  {6}^{2}  \\  {x}^{2}  = 100 - 36 \\

{x}^{2}  = 64 \\  \sqrt{ {x}^{2} }  =  \sqrt{64}  \\ x = 6

3 0
2 years ago
Which value of n makes the following equation true?
grin007 [14]

Answer: d. 512

Step-by-step explanation:

You need to remember that:

(\sqrt[3]{x})^3=x

Then, given the equation:

\sqrt[3]{n}=8

You can find the value of "n" that make the equation true, by solving for "n".

So, to solve for "n", you need to raise both side of the equation to power 3. Therefore, you get:

 \sqrt[3]{n}=8

 (\sqrt[3]{n})^3=(8)^3

 n=512

Then, the value of "n" that makes the equation \sqrt[3]{n}=8 true is: 512 (You can observe that this matches with the option d).

6 0
3 years ago
A rectangle has a height of 4w^3 and a width of 5w^2-3w-4.
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Area of the entire rectangle = height * width

= 4w³ *( 5w²-3w-4)

= 4w³ * 5w²- 4w³ *3w - 4w³ *4

=20w⁵ - 12w⁴ - 16w³

6 0
3 years ago
Read 2 more answers
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