Find x A. X = 23 B. X = 31 C. X = 62 D. X = 118
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Answer:
Step-by-step explanation:
Well we can start by seeing if the parabola is the same width by comparing it to its parent function ( y = x^2 )
In y = x^2 the 2nd lowest point is just up 1 and right 1 away from the vertex.
This is not true for our parabola.
So we can widen it by to the desidered width by making the x^2 into a .5x^2.
So far we’ve got y = .5x^2
Now the parabola y intercept is at -5.
So we can add a -5 into the equation making it.
y = .5x^2 - 5
Now for the x value.
So we can find the x value by seeing how far away the parabola is from from the y axis.
So the x value is -2x.
So the full equation is
Look at the image below to compare.
The resulting function g(x) is ...
g(x) = f(x +1)
g(x) = (((x +1) +1)(x +1) -2)(x +1) +1
= ((x +2)(x +1) -2)(x +1) +1
= (x² +3x)(x +1) +1
= x³ +4x² +3x +1
The shifted function g(x) is ...
g(x) = x³ +4x² +3x +1
g(x) = f(x +1)
g(x) = (((x +1) +1)(x +1) -2)(x +1) +1
= ((x +2)(x +1) -2)(x +1) +1
= (x² +3x)(x +1) +1
= x³ +4x² +3x +1
The shifted function g(x) is ...
g(x) = x³ +4x² +3x +1