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AfilCa [17]
2 years ago
5

Who ever answers ths is 52 minutes will get brainlyeiest

Mathematics
2 answers:
andriy [413]2 years ago
5 0

Answer:

6r+6

Step-by-step explanation:

we dont know the variable's number value yet so you can't solve anything with the 6r. We use distribbutive property and solve 8-2 since the 8 is just subtracting everything in the parenthesis. 8-2=6 and you can't do anything with the 6r so the expression would end up as 6r+6.

Klio2033 [76]2 years ago
4 0

Answer:

-6r+6

Step-by-step explanation:

Let us expand the expression:

8-(6r+2)=

8-6r-2=

6-6r

OR

-6r+6

<em>I hope this helps! :)</em>

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Answer: sorry its not big enough to see sorry

Step-by-step explanation:

6 0
3 years ago
ZE and ZF are vertical angles with mZE = 8x + 8 and mZF = 2x +38.<br> What is the value of x?
Dovator [93]

Answer:

Since ZE and ZF are vertical angles, they are congruent.

8x+8 = 2x+38

8 = 2x-8x+38

8 = -6x+38

8-38 = -6x

-30 = -6x

x = -30/-6

x = 5

7 0
3 years ago
Read 2 more answers
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

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\\  \\

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\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
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lorasvet [3.4K]

\sqrt{2} (3\sqrt{2} )

Here we can simplify the product by multiply the square root 2 with square root 2 first.

3*\sqrt{2} \sqrt{2}

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So answer is 6

4 0
3 years ago
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Answer:

I think it will be $16.50

Step-by-step explanation:

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8 0
3 years ago
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