Answer:
Explanation:
The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark.
If the resistor in the circuit is 1 megaohlm, the total resistance in daylight and darkness will be 1.01 megaohms and 1.1 megaohlms.
The percentage difference = (1.1-1.01)/1.1*100% = 8.18%
If the resistor in the circuit is 25 kohlm, the total resistance in daylight and darkness will be 35 kohms and 125 kohlms.
The percentage difference = (125-35)/125*100% = 72%
With the input p.d to the sensing circuit fixed at 12 v, the sensing current will change according to the total resistance. A 72% difference is much more detectable. So the 25 kohm resistor is the better choice.
Answer:
example two
Explanation:
They have the greatest masses and close proximety relative to the rest, (If you have two black holes each with a solar mass only 1 mile away from one another, they will be highly atracted and probly
orbit each other once a second or so. But now lets try to put the earth and moon one half mile away from each other, they orbit each other much much slower then the two black holes, its becuase the gigantic mass of the black holes overwalms the closser distance between earth and the moon
Have a great day,
enjoy life.
Answer:1.33 hr
Explanation:
Given
Speed of airplane relative to air=627 km/h
Distance traveled =787 km
Speed of wind=38.4 km/h
Wind is blowing in opposite direction therefore net speed is
thus time taken is
Answer:
5.33*10^-3 seconds
Explanation:
c = d/t
c = speed of light constant (3.0*10^5 km/s)
d = distance (1600 km)
t = ?
3.0*10^5 = 1600/t
t = 1600/3.0*10^5
t = 5.33*10^-3 seconds
I hope this helped! :)
