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ExtremeBDS [4]
3 years ago
10

PLEASE HELP MEEEEEEE

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0
Answer: 50

Substitute 0 for x

Y = 75(0)+50

Y= 50
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How to solve this problem?
makkiz [27]
The answer is c because, if u change 15% to a decimal (0.15) then u get 5,250 and when u add that to 35,000 you get 40,250
3 0
3 years ago
Surveys indicate that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner. If there are 500 voters
olya-2409 [2.1K]

<u>Answer:</u>

333 people of ward 5 are going to be voting for Spike Jones.

<u>Solution:</u>

We have been given that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner.  

There are 500 voters in Ward 5.

Since 2/3 of all voters in Ward 5 are voting for Spike Jones the remaining 1/3 will not be voting for him.

To find out how many people in ward 5 are exactly voting for Spike Jones. We need to calculate how much is two thirds of 500 is.

This is done as follows:

\begin{array}{l}{\frac{2}{3} \times 500} \\\\ {=\frac{1000}{3}} \\\\ {=333.334}\end{array}

Since people cannot be denoted in decimal points we have to round it off to a whole number. That’s is 333.

Therefore 333 people of ward 5 are going to be voting for Spike Jones.

4 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
SEE IMAGE! Two lines below intersect to form four angles, as shown. The measure of angle 2 is 114°. What is the sum of the measu
o-na [289]
ANSWER:


Angles 2 and 4 are vertical angles, which means they have the same angle measure because they are opposite of each other. So angles 2 and 4 are both 114 so that makes 228. All of the angles have to make 360, so 360 - 228 = 132. Then, 132/2 because there are two angles. That makes 66. And angles 1 and 3 are also vertical angles so they are also the same

The answer is 132
8 0
3 years ago
Use math drawings to make pictures equal
gavmur [86]
Well, what are the pictures??
5 0
4 years ago
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