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Igoryamba
3 years ago
7

Find two numbers if there sum is 7.2 and their difference is 2.7

Mathematics
2 answers:
Sidana [21]3 years ago
6 0

Answer:

2.25 and 4.95

Step-by-step explanation:

x + y = 7.2

x - y = 2.7

x = 7.2 - y

x - y = 2.7

(7.2 - y) - y = 2.7

7.2 - 2y = 2.7

-2y = 2.7 - 7.2

-2y = -4.5

-2y/-2 = -4.5/-2

y = 2.25

x + y = 7.2

x + 2.25 = 7.2

x = 7.2 - 2.25

x = 4.95

Check: 4.95 and 2.25

x + y = 7.2

(4.95) + (2.25) = 7.2

7.2 = 7.2

x - y = 2.7

(4.95) - (2.25) = 2.7

2.7 = 2.7

sveta [45]3 years ago
3 0

Answer:

x+y=7.2

x-y=2.7

Step-by-step explanation:

equation

x+2.7+x=7

2x=4.3

x=4.3/2

y=7-4.3/2

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Answer:

$4,711.31

Step-by-step explanation:

Calculation for Jennifer's monthly gross pay

First step is to calculate The total tax percentage deductions

Using this formula

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8 0
2 years ago
What two numbers multiply to 44 and add up to 12?
djverab [1.8K]
This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.

let the two numbers be x and y.

Multiply to 44.      x*y = 44 ..........(a)

Add up to 12.      x + y = 12 .........(b)

From (b)

y = 12 - x .......(c)

Substitute (c) into (a)

x*y = 44

x*(12 - x) = 44   

12x - x² = 44

-x² + 12x = 44

-x² + 12x - 44 = 0.       

Multiply both sides by -1

-1(-x² + 12x - 44) = -1*0

x² - 12x + 44 = 0.   

This does not look factorizable, so let us just use quadratic formula

comparing to ax² + bx + c = 0, x² - 12x + 44 = 0,  a = 1, b = -12, c = 44 

x = (-b + √(b² - 4ac)) /2a   or (-b - √(b² - 4ac)) /2a


x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)    

x = (12 + √(144 - 176) )/ 2

x = (12 + √-32 )/ 2

√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2

Where i is a complex number.  Note the equation has two values. We shall include the second, that has negative sign before the square root.

x = (12 + √-32 )/ 2      or     (12 - √-32 )/ 2   

x = (12 + 4i√2 )/ 2              (12 - 4i√2 )/ 2 

x = 12/2 + (4i√2)/2                12/2 - (4i√2)/2

x = 6 + 2i√2            or         6 - 2i√2

Recall equation (c):

y = 12 - x, When x = 6 + 2i√2,  y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2

When x = 6 - 2i√2,  y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2


x = 6 + 2i√2,  y = 6 - 2i√2

x = 6 - 2i√2,  y = 6 + 2i√2

Therefore the two numbers that multiply to 44 and add up to 12 are:

6 + 2i√2 and 6 - 2i√2
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