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My name is Ann [436]
3 years ago
15

Solve for n: 3n + 2n - 17 = 38

Mathematics
2 answers:
Lyrx [107]3 years ago
8 0
Get all the n together so 3n+2n=5n
5n-17=38
Minus 17 from both sides
5n= 55
N= 11
Arlecino [84]3 years ago
3 0
First you +17 to both sides to get 3n+2n=55
then you do 3n+2n= 5n
so you have 5n=55
so then n=11
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19/3×17/4×5/4=1615/48

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your mom        Step-by-step explanation:

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3 years ago
Which ordered pair makes both inequalities true?
Digiron [165]
For a
0 > -3(1) + 3 i.e. 0 > 0 (not true)
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1 > -3(-1) + 3 i.e. 1 > 6 (not true)
For c
2 > -3(2) + 3 i.e. 2 > -3 (true)
2 > 2(2) - 2 i.e. 2 > 2 (not true)
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3 > -3(0) + 3 i.e. 3 > 3 (not true)

Therefore, none of the ordered pairs makes both inequalities correct.
5 0
3 years ago
Read 2 more answers
Mei's average score on the first six holes in a miniature golf game was 6. her average score on the next 12 holes was 3. what wa
yanalaym [24]

Answer:

72

Step-by-step explanation:

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3 0
3 years ago
Identify the quotient in the form a + bi. HELP ASAP PLEASE!!
Artist 52 [7]

Solving \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

Option A is correct.

Step-by-step explanation:

We need to find the result of \frac{4-5i}{2+3i}

We need to remove i from the denominator. For removing i Multiplying and dividing by 2-3i:

\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}

Solving:

=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i*(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,i^2=-1\\=\frac{8-12i-10i+15(-1))}{4-9(-1)}\\=\frac{8-12i-10i-15}{4+9}\\=\frac{8-15-12i-10i}{13}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}

So, solving \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

  • brainly.com/question/10736268
  • brainly.com/question/4678474

#learnwithBrainly

5 0
3 years ago
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